Treatment of hydroxylamine (H2NOH) with an excess of Fe (III) results in the formation of N2O and an equivalent amount of Fe (II): 2 H2NOH + 4 F e3+ N2O(g) + 4 Fe2+ + 14 H+ + H2O Calculate the molar concentration of an H2NOH solution if the Fe (II) produced by treatment of a 49.00 -mL aliquot required 11.86 mL of 0.0556 M K2Cr2O7. Cr2O72- + 6 Fe2+ + 12 H+ 2 Cr3+ + 6 Fe 3+ + 7 H2O

Here we have to determine the molar concentration of NH2OH in the following given volumetric…

Answered: Treatment of hydroxylamine (H2NOH) with…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter4: Types Of Chemical Reactions And Solution Stoichiometry

Section: Chapter Questions

Problem 47E

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Treatment of hydroxylamine (H₂NOH) with an excess of Fe (III) results in the formation of N₂O and an equivalent amount of Fe (II):

2 H₂NOH + 4 F e³⁺ N₂O(g) + 4 Fe²⁺ + 14 H⁺ + H₂O

Calculate the molar concentration of an H₂NOH solution if the Fe (II) produced by treatment of a 49.00 -mL aliquot required 11.86 mL of 0.0556 M K₂Cr₂O₇.

Cr₂O₇^2- + 6 Fe²⁺ + 12 H⁺ 2 Cr³⁺ + 6 Fe ³⁺ + 7 H₂O

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