True False  Suppose a stationary police officer at point A sees you pass by at 5:10pm and his colleague 10 Miles down the road at point B sees you pass at 5:16pm. The speed limit is 65MPH between point A and point B. They can then prove you must have broken the speed limit at some point between A and B. You may assume that your position as a function of time is both continuous and dirferentiable everywhere. Your justification should cite a theorem.

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Chapter1: Functions
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Suppose a stationary police officer at point A sees you pass by at 5:10pm and his colleague 10 Miles down the road at point B sees you pass at 5:16pm. The speed limit is 65MPH between point A and point B. They can then prove you must have broken the speed limit at some point between A and B. You may assume that your position as a function of time is both continuous and dirferentiable everywhere. Your justification should cite a theorem.

Expert Solution
Step 1

Lets first calculate the average speed.

Time taken between point A and point B = 5:16 pm - 5:10 pm = 6 mins = 6/60 = .1 hour

Distance traveled = 10 Miles

Average speed = Distance/time = 10/.1 = 100 MPH

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