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ture 12 Part 2: Coplanar Equilibrium Equations; Equilibrium Analysis of Single Bodies a ActivePresenter Let's Practice! Practice Problem: Given: Determine the horizontal and vertical components supports. Neglect the thickness of the beam. of reaction at the 500 lb 600 lb ft 5 ft -5 ft -5 ft Answer: = 140 lb(upward) Ay = = 300 lb (left) = 260 lb(upward) NB Scroll for details CC Prepere 29.19/29.34

ture 12 Part 2: Coplanar Equilibrium Equations; Equilibrium Analysis of Single Bodies a ActivePresenter Let's Practice! Practice Problem: Given: Determine the horizontal and vertical components supports. Neglect the thickness of the beam. of reaction at the 500 lb 600 lb ft 5 ft -5 ft -5 ft Answer: = 140 lb(upward) Ay = = 300 lb (left) = 260 lb(upward) NB Scroll for details CC Prepere 29.19/29.34

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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ecture 12 Part 2: Coplanar Equilibrium Equations; Equilibrium Analysis of Single Bodies O ActivePresenter Let's Practice! Practice Problem: Given: Determine the horizontal and vertical of reaction at the components supports. Neglect the thickness of the beam. 500 lb 600 lb ft A -5 ft -5 ft -5 ft Answer: Ay = 140 lb(upward) Ax = 300 lb (left) = 260 lb(upward) Scroll for details CC Propan 29:19/29:34 HB 1080
Transcribed Image Text:ecture 12 Part 2: Coplanar Equilibrium Equations; Equilibrium Analysis of Single Bodies O ActivePresenter Let's Practice! Practice Problem: Given: Determine the horizontal and vertical of reaction at the components supports. Neglect the thickness of the beam. 500 lb 600 lb ft A -5 ft -5 ft -5 ft Answer: Ay = 140 lb(upward) Ax = 300 lb (left) = 260 lb(upward) Scroll for details CC Propan 29:19/29:34 HB 1080
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