This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come backto the skipped part.Tutorial ExerciseThe annual net income of a company for the period 2007-2011 could be approximated byP(t)1.6t2- 15t + 45 billion dollars(2 0, in which case the parabola opens upward. Thegraph of a parabola is called concave down if a < 0, in which case the parabola opens downward. In this case,because a is ---Select--- v, the parabola is concave ---Select--- v. So the lowest point on the parabola is thea =b =and c =vertex.

Tutorial Exercise The annual net income of a company for the period 2007-2011 could be approximated by P(t) = 1.6t? – 15t + 45 billion dollars (2 sts 6), where t is the time in years since the start of 2005. According to the model, during what year in this period was the company's net income the lowest? What was the corresponding net income? Would you trust this model to continue to be valid long past this period? Why or why not? Step 1 The annual net income of a company for the time period 2007–2011 is given by the quadratic function P(t) = 1.6t? - 15t + 45 billion dollars, where the inputs for t are 2sts 6. We are looking for the time t for which the company's net income was the lowest. Notice that the income function is a quadratic function of the form P(t) = at? + bt + c, where a = parabola. The graph of a parabola is called concave up if a > 0, in which case the parabola opens upward. The graph of a parabola is called concave down if a < 0, in which case the parabola opens downward. In this case, because a is --Select--- v , the parabola is concave --Select--- v. So the lowest point on the parabola is the ,b = , and c = ]. The graph of the quadratic function is a vertex.