Tutorial Exercise You are given the dollar value of a product in 2016 and the rate at which the value of the product is expected to change during the next 5 years. Write a linear equation that gives the dollar value V of the product in terms of the year t. (Let t= 0 represent 2010.) 2016 Value $3,100 Rate $400 Increase per year Step 1 Recall that the slope of the line can be interpreted as a rate of change. In this case, the value Increases as time passes and the rate of change is $400 per year. change in value (in dollars) rate of change change in time (in years) 400 400 400 Therefore, the slope m of the linear function is m = 400/1 400 Step 2 We are to let t= 0 represent 2010. In 2016 the dollar value is given to be $3,100. Therefore, V= 3,100 when t = This point on the graph of the linear function can be defined as (t₂, v₂) = (C 3,100) x.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter4: Equations Of Linear Functions
Section4.1: Writing Equations In Slope-intercept Form
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Tutorial Exercise
You are given the dollar value of a product in 2016 and the rate at which the value of the product is expected change during the next 5 years. Write a linear equation that gives the dollar value V of the product in terms of the year t. (Let t = 0 represent 2010.)
2016 Value
$3,100
400
T
= 400
Rate
$400 Increase per year
Step 1
Recall that the slope of the line can be interpreted as a rate of change. In this case, the value Increases as time passes and the rate of change is $400 per year.
change in value (in dollars)
rate change=
change in time (In years)
400
Therefore, the slope m of the linear function is m = 400/1
400
Step 2
We are to let t = 0 represent 2010. In 2016 the dollar value is given to be $3,100. Therefore, V = 3,100 when t =
This point on the graph of the linear function can be defined as (t₁, v₁) = (
, 3,100).
Submit Skip (you cannot come back)
1x
Transcribed Image Text:Tutorial Exercise You are given the dollar value of a product in 2016 and the rate at which the value of the product is expected change during the next 5 years. Write a linear equation that gives the dollar value V of the product in terms of the year t. (Let t = 0 represent 2010.) 2016 Value $3,100 400 T = 400 Rate $400 Increase per year Step 1 Recall that the slope of the line can be interpreted as a rate of change. In this case, the value Increases as time passes and the rate of change is $400 per year. change in value (in dollars) rate change= change in time (In years) 400 Therefore, the slope m of the linear function is m = 400/1 400 Step 2 We are to let t = 0 represent 2010. In 2016 the dollar value is given to be $3,100. Therefore, V = 3,100 when t = This point on the graph of the linear function can be defined as (t₁, v₁) = ( , 3,100). Submit Skip (you cannot come back) 1x
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