Two 25.0-mL solutions of 0.100 M Ba²+ are titrated with 0.100 M EDTA at pH 10. Calculate the value of pBa²+ for each titration after the addition of 0, 10.0, 25.0, and 30.0 mL of titrant. After the addition of 0 mL EDTA = After the addition of 10.0 mL EDTA = After the addition of 25.0 mL EDTA = After the addition of 30.0 mL EDTA = Type your answer here Type your answer here Type your answer here Type your answer here

Two 25.0-mL solutions of 0.100 M Ba²+ are titrated with 0.100 M EDTA at pH 10. Calculate the value of pBa²+ for each titration after the addition of 0, 10.0, 25.0, and 30.0 mL of titrant. After the addition of 0 mL EDTA = After the addition of 10.0 mL EDTA = After the addition of 25.0 mL EDTA = After the addition of 30.0 mL EDTA = Type your answer here Type your answer here Type your answer here Type your answer here

Appl Of Ms Excel In Analytical Chemistry

2nd Edition

ISBN:9781285686691

Author:Crouch

Publisher:Crouch

Chapter7: Neutralization Titrations And Graphical Representations

Section: Chapter Questions

Problem 10P

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