Two forces, F, - (6,551 - 5.75) Nand F, - (301 - 3.55) N, act on a particle ofmass 1.80 kg that is initially at rest at coordinates(+2.20 m, +3.85 m).(a) What are the components of the particle's velocityat t = 11.2 s?%3Dm/s(b) In what direction is the particle moving at t = 11.2s?° counterclockwise from the +x-axis(c) What displacement does the particle undergoduring the first 11.2 s?A: =m(d) What are the coordinates of the particle at t = 11.2s?y =

Given data:initial velocity u=0m/sF→1=(6.55i-5.75j)NF→2=(3.30i-3.55j)Ninitial position…

Two forces, F, - (6,51 - 5,5) N and F,- (3.301 - 3.5)N. Act on a particle of mass 1.80 kg that is initially at rest at coordinates (+2.20 m, +3.85 m). (a) What are the components of the particle's velocity at t = 11.2 s?

Two forces, F, - (6,51 - 5,5) N and F,- (3.301 - 3.5)N. Act on a particle of mass 1.80 kg that is initially at rest at coordinates (+2.20 m, +3.85 m). (a) What are the components of the particle's velocity at t = 11.2 s?

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter9: Momentum And Its Conservation

Section: Chapter Questions

Problem 72A

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Concept explainers

Newton’s Third Law of Motion

The horse pulls the cart and the cart pulls the horse in response as per Newton third law. So the big question is, “Don’t the two forces cancel each other? How does the cart accelerate?”

Question

Two forces, F, - (6,551 - 5.75) N
and F, - (301 - 3.55) N, act on a particle of
mass 1.80 kg that is initially at rest at coordinates
(+2.20 m, +3.85 m).
(a) What are the components of the particle's velocity
at t = 11.2 s?
%3D
m/s
(b) In what direction is the particle moving at t = 11.2
s?
° counterclockwise from the +x-axis
(c) What displacement does the particle undergo
during the first 11.2 s?
A: =
m
(d) What are the coordinates of the particle at t = 11.2
s?
y =

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