Two forces, F and F2, act at a point. F1 has a magnitude of 9.80 N and is directed at an angle of 65.0 ° above the negative x axis in the second quadrant. F2 has a magnitude of 6.40 N and is directed at an angle of 54.1 ° below the negative x axis in the third quadrant.
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A: Given Data : F1 = 5.5Ni - 8.4Nj + 7.1Nk F2 = 7.8Ni - 1.4Nj - 3.8Nk
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A: Resultant of FA→ and FB→ is R=FA2+FB2+2FAFBcos1440 Charles must pull with this magnitude for…
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Q: An antelope is being pulled by two forces whose vector-component expressions are: F1 = 6Ni + 7.3Nj…
A: The angle between two forces is given by F→1·F→2=F1F2cosθθ=cos-1F→1·F→2F1F2 The dot product between…
Q: An antelope is being pulled by two forces whose vector-component expressions are: F1- 0.9NI + -3.1Nj…
A: The given vectors, F→1=0.9 Ni^+3.1 Nj^+9.9 Nk^F→2=6.7 Ni^+8.6 Nj^+9.4 Nk^ The angle between the…
Q: An antelope is being pulled by two forces whose vector-component expressions are: F1 = 0.9Ni +…
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Q: An antelope is being pulled by two forces whose vector-component expressions are: F1 = -2.6Ni + 5Nj…
A: Angle between two vector F⇀1·F⇀2=F1F2cosθθ=cos-1F⇀1·F⇀2F1F2
Q: An antelope is being pulled by two forces whose vector components are : f1 =-2.6Ni+5Nj +-6.1Nk f2…
A: Angle between two vectors can be calculated by dot product or cross product. The easier approach is…
Q: An antelope is being pulled by two forces whose vector-component expressions are: F1 = -1.3Ni +…
A: Given, Two force vectors
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Q: An antelope is being pulled by two forces whose vector-component expressions are: F1 = -6Ni +…
A: Given: F→1=-6i⏜-7.5j⏜-9.2k⏜F→2=-0.9i⏜+0.1j⏜-6.7k⏜
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Q: An antelope is being pulled by two forces whose vector-component expressions are: F1 = -8.9Ni +…
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Q: An antelope is being pulled by two forces whose vector-component expressions are: F1 = -9.3Ni +…
A: Given vectors, F→1=-9.3i^+7.3j^+9.2k^ NF→2=-1i^-1.2j^+1k^ N Angle between the two force vectors is θ
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Q: An antelope is being pulled by two forces whose vector-component expressions are: F1 = 8.8Ni +…
A: Given data: F1 = 8.8Ni + -9.2Nj + -6.2Nk F2 = 0.1Ni + -8.4Nj + 4.8Nk Required: The angle between…
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Q: An antelope is being pulled by two forces whose vector-component expressions are: F1 = 2.2Ni + 1.5Nj…
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A: Given data: The magnitude of F→1=9.60N Angle α =58.0° The magnitude of F→2=7.00N Angle β =53.7°
Q: An antelope is being pulled by two forces whose vector-component expressions are: F1 = -3.3Ni +…
A: Given forces F1 and F2, the angle between them, θ, is given as, cosθ=u·vuv
Q: An antelope is being pulled by two forces whose vector-component expressions are: F1 = 7.4Ni + 8.2Nj…
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Q: antelope is being pulled by two forces whose vector-component expressions are: F1 = 3.6Ni + -8.9Nj…
A: If multiplication of two vector is a scalar quantity then it called scalar product
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- A force of magnitude 7.50 N pushes three boxes with masses m1=1.30kg ,m2=3.20kg, and m3=4.90kg. Find the magnitude of the contact force between boxes 1 and 2.There are two forces on the 1.19 kg box in the overhead view of the figure but only one is shown. For F1 = 15.7 N, a = 14.7 m/s2, and θ = 34.1°, find the second force (a) in unit-vector notation and as (b) a magnitude and (c) a direction. (State the direction as a negative angle measured from the +x direction.)The two tugboats apply the forces P and Q to the barge, where P=76 kN and Q=52 kN. Determine the resultant of P and Q.
- An antelope is being pulled by two forces whose vector-component expressions are: F1 = 0.7Ni + 0.5Nj + 7.2Nk F2 = 9.9Ni + -9.2Nj + -8.1Nk What is the angle between these two vectors?If the magnitudes f1 and f2 are both equal to 4newtons, what are the horizontal and vertical components of the two forces? F1x=?F1y=?F2x=?F2y=?An antelope is being pulled by two forces whose vector-component expressions are: F1 = -3.5Ni + 3.4Nj + 3.9Nk F2 = 3Ni + 2.6Nj + -1.5Nk What is the angle (in degrees) between these two vectors?
- A rocket is powered by two engines that are angled 12 degrees to the horizontal. Each engine produces 9000N of thrust. What is the magnitude of the net forward force exerted by the rockets engines?In the figure, a slab of mass m1 = 40 kg rests on a frictionless floor, and a block of mass m2 = 10 kg rests on top of the slab. Between block and slab, the coefficient of static friction is 0.60, and the coefficient of kinetic friction is 0.40. A horizontal force F→ of magnitude 104 N begins to pull directly on the block, as shown. In unit-vector notation, what are the resulting accelerations of (a) the block and (b) the slab?A particle is subjected to the action of two forces : F1 = 41+ 3 + 6 k [ kN ] and F2 = 51-61 -5k [ kN ] . The coordinate direction angle of the resultant force with the X - axis is
- Forces P, Q and S of magnitudes 6.00 N, 10.00 N and 8.00 N respectively, acts on point O such that the angle made by force P is 50o counter clockwise from the positive x axis, force Q acts at an angle of 38 o counter clockwise from the negative y axis and force S acts at an angle of 32 o counter clockwise from the positive y axis. The x component of force S isA particle, which remains at rest, is acted on by three forces F, G and H. The force F has magnitude 18N and is directed to the left and down, making an angle of 40 degrees with the vertical. The force G has magnitude 15N and is directed to the right and down, making an angle of 70 degrees with the horizontal. Find the magnitude of the vector H and the acute angle it makes with the horizontal.Three forces act on an object, considered to be a particle, which moves with constant velocity v =(3 m/s)î +(−2 m/s)ĵ Two of the forces are shown in the picture below., while the third force, F_3 is not given. 1.) What are the x, y, and z components of F_3?