5.3 (a) Using the particle under a net force model, we calculate the net force on the object in the first figure.ΣF = F₁+F₂ΣΕ= 27The following is the mathematical statement of Newton's second law.ΣF = maExpressing the sum of the forces in vector notation, and substituting the value of the mass, we haveEF= 2727 + 13.513.5 Ĵ) N = 5.35.3 kg)a.Part 4 of 6 - AnalyzeNow, solving for the acceleration, gives27 Î+ 13.527Xa = Your response differs from the correct answer by more than 100%. Î+ 13.5Your response differs from the correct answer by more than 100%. ĵ) m/s².Remembering that a = a =for the magnitude and directiona =0 = tan-1 ayaX=13.5 Ĵ N2a + aym/s²)² + (2, and substituting for the x and y components of acceleration,m/s²)² ==Xm/s² Two forcesand F₂ act on a 5.30-kg object. F₁1F₂ma90.0⁰= 27.0 N and F₂ = 13.5 N.스L60.0⁰mb(a) Find the acceleration of the object for the configuration of forces shown in Figure (a).(b) Find the acceleration of the object for the configuration of forces shown in Figure (b).

Name: 5.3 (a) Using the particle under a net force model, we calculate the n
Uploaded: 2024-03-20T06:57:57.000Z
Channel: Bartleby
Description: 5.3 (a) Using the particle under a net force model, we calculate the net force on the object in the first figure.ΣF = F₁+F₂ΣΕ= 27The following is the mathematical statement of Newton's second law.ΣF = maExpressing the sum of the forces in vector nota