Two hallways, one of width 5 feet, the other of width 6feet, meet at a right angle. See the illustration to theright. It can be shown that the length L of the ladder as afunction of 0 is L(0) = 6 csc 0 +5 sec 0. Complete parts(a) through (d) below......(a) In calculus, the length of the longest ladder that can turn the corner is found by solving the equation5 sec 0 tan 0 -6 csc e cot 0 =0 for 0 where 0° <0<90°. Solve this equation for 0.0 = 46.74°(Type an integer or decimal rounded to the nearest hundredth as needed.)(b) What is the length of the longest ladder that can be carried around the corner?L= 15.54 feet(Type an integer or decimal rounded to the nearest hundredth as needed.)(c) Graph L = L(0), 0° <0< 90". Choose the correct answer below.O A.OB.O C.OD.AL108-1048-20-4-18-2-6-164 EE6-0-4-4--21141 12-2-124043060 00A 30 6090306090Find the angle that minimizes the length L.0 =(Type an integer or decimal rounded to the nearest hundredth as needed.)(d) Compare the result in part (c) with the one found in part (a). Explain.O A. The answers in part (c) and part (a) are oqual because the angle that minimizes the length of the ladder is the same asthe angle at which the longest ladder can be carried around the corner based on the illustration.O B. The answer in part (a) is greater than the answer in part (c) because part (c) shows the angle that minimizes the lengthof the ladder. Part (a), on the other hand, shows the angle that maximizes the length of the ladder.Oc. The answers in part (c) and part (a) are equal because L(0)-6 csc0+ 5 sec 0-5 sec 0 tan 0-6 csc 0 cot 0.OD. The answer in part (c) is greater than the answer in part (a) because the angle in part (a) shows the angle at which thelength of the ladder is 0, meaning that no ladder can be carried around the cormer. Part (0), on the other hand, shows themaximum length of a ladder than can be carried around the corner.

We have to find θ,L and graph it. According to our guidelines we can solve only 3 subparts so…

Two hallways, one of width 5 feet, the other of width 6 feet, meet at a right angle. See the illustration to the right. It can be shown that the length L of the ladder as a function of 0 is L(0) = 6 csc 0+ 5 sec 0. Complete parts (a) through (d) below. (a) In calculus, the length of the longest ladder that can turn the corner is found by solving the equation 5 sec 0 tan 0 -6 csc 0 cot 0=0 for 0 where 0<0<90". Solve this equation for 0. - 46.74° Type an integer or decimal rounded to the nearest hundredth as needed.) b) What is the length of the longest ladder that can be carried around the corner? = 15.54 feet Type an integer or decimal rounded to the nearest hundredth as needed.) (c) Graph L L(0), 0" <0<90", Chooso the correct answor bolow. OA. B. OC. OD. AL 104 AL 104 8- 20 4- 18- 2- 16 4- 14- 4- 2- 2- 12 30 60 30 60 00 30 60 0

Two hallways, one of width 5 feet, the other of width 6 feet, meet at a right angle. See the illustration to the right. It can be shown that the length L of the ladder as a function of 0 is L(0) = 6 csc 0+ 5 sec 0. Complete parts (a) through (d) below. (a) In calculus, the length of the longest ladder that can turn the corner is found by solving the equation 5 sec 0 tan 0 -6 csc 0 cot 0=0 for 0 where 0<0<90". Solve this equation for 0. - 46.74° Type an integer or decimal rounded to the nearest hundredth as needed.) b) What is the length of the longest ladder that can be carried around the corner? = 15.54 feet Type an integer or decimal rounded to the nearest hundredth as needed.) (c) Graph L L(0), 0" <0<90", Chooso the correct answor bolow. OA. B. OC. OD. AL 104 AL 104 8- 20 4- 18- 2- 16 4- 14- 4- 2- 2- 12 30 60 30 60 00 30 60 0

Elementary Algebra

17th Edition

ISBN:9780998625713

Author:Lynn Marecek, MaryAnne Anthony-Smith

Publisher:Lynn Marecek, MaryAnne Anthony-Smith

Chapter9: Roots And Radicals

Section9.4: Multiply Square Roots

Problem 311E: An artist wants to make a small monument in the shape of a square base topped by a right triangle,...

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