Two horizontal plates of opposite charge form a constant electric field = 1000 N/C directed vertically downwards. An electron of mass me and charge e* is fired horizontally with velocity v = 0.1c, where c = 3.00 x 108 m/s between the plates. Calculate the electron's acceleration. If the plates have length 1 m, find the electron's deflection from the horizontal when it emerges.

Principles of Physics: A Calculus-Based Text
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ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
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Chapter19: Electric Forces And Electric Fields
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Two horizontal plates of opposite charge form a constant electric field = 1000 N/C directed
vertically downwards. An electron of mass me and charge e* is fired horizontally with velocity v =
0.1c, where c = 3.00 x 108 m/s between the plates. Calculate the electron's acceleration. If the
plates have length 1 m, find the electron's deflection from the horizontal when it emerges.
Transcribed Image Text:Two horizontal plates of opposite charge form a constant electric field = 1000 N/C directed vertically downwards. An electron of mass me and charge e* is fired horizontally with velocity v = 0.1c, where c = 3.00 x 108 m/s between the plates. Calculate the electron's acceleration. If the plates have length 1 m, find the electron's deflection from the horizontal when it emerges.
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