# Two large, parallel, conducting plates are 15 cm apart and have charges of equal magnitude and opposite sign on their facing surfaces. An electrostatic force of 4.8 × 10-15 N acts on an electron placed anywhere between the two plates. (Neglect fringing.) (a) Find the electric field at the position of the electron. (b) What is the potential difference in volts between the plates?

Question
Asked Jun 20, 2019
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Two large, parallel, conducting plates are 15 cm apart and have charges of equal magnitude and opposite sign on their facing surfaces. An electrostatic force of 4.8 × 10-15 N acts on an electron placed anywhere between the two plates. (Neglect fringing.) (a) Find the electric field at the position of the electron. (b) What is the potential difference in volts between the plates?

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Step 1

Given

Distance between the plates d = 15 cm = 0.15 m

Electrostatic force on electron F = 4.8 x 10-15 N

Known value

Charge of an electron q = 1.6 x 10-19 C

Solution

A) Finding the electric field

Step 2

B) Finding Potential Differ...

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