Question

Asked Jun 20, 2019

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Two large, parallel, conducting plates are 15 cm apart and have charges of equal magnitude and opposite sign on their facing surfaces. An electrostatic force of 4.8 × 10^{-15} N acts on an electron placed anywhere between the two plates. (Neglect fringing.) **(a)** Find the electric field at the position of the electron. **(b)** What is the potential difference in volts between the plates?

Step 1

**Given**

Distance between the plates d = 15 cm = 0.15 m

Electrostatic force on electron F = 4.8 x 10^{-15} N

**Known value**

Charge of an electron q = 1.6 x 10^{-19} C

**Solution**

**A) Finding the electric field**

Step 2

**B) Finding Potential Differ...**

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