Two speakers create identical 288 Hz sound waves. A person is 1.47 m from Speaker 1. What is the MINIMUM distance to Speaker 2 for there to be constructive interference at that spot? (Hint: v = \f = 343 m/s) (Unit = m)
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- Two speakers, 7.0 m apart, are in phase and emit a pure tone of wavelength 2.0 meters. The closest loud spot (completely constructive interference) to either speaker along a line segment connecting the speakers is how many meters away?Two out of phase loudspeakers are some distance apart. A person stands 5.30 m from one speaker and 2.60 m from the other. What is the third lowest frequency at which constructive interference will occur? The speed of sound in air is 338 m/s.Two identical loudspeakers 2.0 m apart are emitting 1800 Hz sound waves into a room where the speed of sound is 340 m/s. Is the point 4.0 m directlyin front of one of the speakers, perpendicular to the line joining the speakers, a point of maximum constructive interference, perfect destructive interference, or something in between?
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- Two loudspeakers, placed on opposite walls of a 10m long room, emit pure sine waves with f = 170 Hz coherently. If we were exactly in the middle of the room, where the waves are interfering constructively, what is the shortest distance we should travel towards one of the speakers so that the waves cancel out completely? Assume the speed of sound in air is 340 m/s.Two loudspeakers are placed above and below each other, as in the figure, and driven by the same spice at a frequency of 5.60* 10^2 Hz. An observer is in front of the speakers at point O, at the same distance from each speaker. What max vertical distance upward should the top speaker be moved to create destructive interference at point O? ( assume spread of sound is 343m/s)Two loudspeakers, placed with respect to an observation point P as shown in the diagram below, emit identical pure tones of f = 343 Hz. The speed of sound in air is 343 m/s. The minimum speaker separation s for experiencing complete destructive interference at P is s = m.
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