-Two word wide unsigned integers are stored at the physical memory addresses 00A00 and 00A02, respectively. Write an instruction sequence that computes and stores their sum, difference, product, and quotient. Store these results at consecutive memory locations starting at physical address 00A10 in memory. To obtain the difference, subtract the integer at 00A02 from the integer at 00A00. For the division divide the integer at 00A00 by the integer at 00A02. Use the register indirect relative addressing mode to store the various results.
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A: The question is to write the ALP for the given problem.
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A: Here is the solution:
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A: Answer is given below .
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Q: Q) 2. Answer the following: A. What happens if AL=20h and AH= 10h. When each of the following…
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Q: 2. Two word-wide unsigned integers are stored at the physical memory addresses 00A0016 and 00A0216,…
A: Two word-wide unsigned integers are stored at the physical memory addresses 00A0016 and 00A0216,…
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A:
Q: Read the following code carefully to answer what it does: START: MOV SI, 0300 MOV DI, 0302 MOV AX,…
A: We need to find the correct option regarding the given assembly code.
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Q: Q4/ A- write a program to count number of one's & zero's in a number stored at 0200:0010, use rotate…
A: Answer is given below .
Q: Two word-wide unsigned integers are stored at the physical memory address 00A0016 and 00A0216 ,…
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A: This is very simple. ----------------------------------------------------- SIC Sequence of…
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A: Here is the answer:-
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A: The above question is solved in step 2:-
Q: -Write a single instruction that will load AX from address [1F22 H] and DS from address [1F24 H].
A: TO load AX from address [1F22 H] using MOV instruction:- MOV AX, [1F22H]
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Q: Two word-wide unsigned integers are stored at the physical memory address 00A0016 and 00A0216 ,…
A: Given: Two word-wide unsigned integers are stored at the physical memory address 00A0016and 00A0216…
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A: Actually, 1 byte= 8 bits.
Q: 52-Two word wide unsigned integers are stored at the physical memory addresses 00A00 and 00A02,…
A: Given:- Two word wide unsigned integers are stored at the physical memory addresses 00A00 and 00A02…
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A: The Answer is
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A: Given: The registers holding the variables are as follows: $s1 ← A $s2 ← B $t1 ← i $t2 ← temp
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- Q) Write a program in assembly language to compares the elements of two arrays, A(1) and B(1), each array contains 100 16-bit signed number. Assume that the arrays start in the current data segment at offset addresses A000H and B000H respectively. If the two arrays are found to be unequal, save the address of the first unequal element of A(1) in the memory location with offset F00011. Otherwise, if the two arrays are found to be equal, write all O's into this location.Trace the following Code and then print the output. msg db 'hello world$' newline db 10,13,'$' buffer db 10 dup mov ah,9 mov dx,offset msg int 21h ;new line mov ah,9 mov dx, offset newline int 21h ;enter a string from the keyboard lea dx,buffer mov ah,0ah int 21h ;new line mov ah,9 mov dx,offset newline int 21h ;adding the $ symbol at the end of the string mov bx,0 mov bl,buffer[1] mov buffer[bx+2],'$' mov ah,9 mov dx,offset buffer+2 int 21hQ2: Write a Assembly language program that copies the BYTES from array V1 to array V2 using indexed addressing, PTR Operator and LOOP such that after execution of your code the elements of V2 will become [78h, 56h, 34h, 12h, 21h, 43h, 65h, 87h]. The data is given in the data segment below .data v1 DWORD 12345678h, 87654321h
- which instructions best apply to the following prompt Implement an open addressing hash table to store a list of integers. Your task is to handle collisions using open addressing and implement basic operations such as insertion, deletion, and searching. The open addressing technique you will use is linear probing.1.use open addressing2.implement this in python3.use double hashing 4.use linear probing5.implement an open addressing hash table to store integersc programming language The program below uses pointer arithmetic to determine the size of a 'char'variable. By using pointer arithmetic we can find out the value of 'cp' and thevalue of 'cp+1'. Since cp is a pointer, this addition involves pointer arithmetic:adding one to a pointer makes the pointer point to the next element of the sametype.For a pointer to a char, adding 1 really just means adding 1 to the address, butthis is only because each char is 1 byte.1. Compile and run the program and see what it does.2. Write some code that does pointer arithmetic with a pointer to an int anddetermine how big an int is.3. Same idea – figure out how big a double is, by using pointer arithmetic andprinting out the value of the pointer before and after adding 1.4. What should happen if you added 2 to the pointers from exercises 1through 3, instead of 1? Use your program to verify your answer.#include <stdio.h>int main( ){ char c = 'Z'; char *cp = &c; printf("cp is %p\n", cp);…4) Answer the question in C++ A) What is wrong with the following code segment? enum CarType {GM, FORD, BMW}; int main() { CartType = BMW; return 0; } B) Assume that the addresses of x and y is 0x61feb8 and 0x61feb0, respectively. What will be the values of x, y, p, and q, respectively, when the following code runs successfully? int main() { int x; double y; int* p = &x; double* q = &y; *p = 3; *q = 3.14; increaseByOne(p, q); cout << x << " " << y << endl; cout << p << " " << q << endl; return 0; }void increaseByOne(int*& p1, double* q1){ (*p1)++; (*q1)++; p1++; q1++;} The four value:
- The program below uses pointer arithmetic to determine the size of a 'char'variable. By using pointer arithmetic we can find out the value of 'cp' and thevalue of 'cp+1'. Since cp is a pointer, this addition involves pointer arithmetic:adding one to a pointer makes the pointer point to the next element of the sametype.For a pointer to a char, adding 1 really just means adding 1 to the address, butthis is only because each char is 1 byte.1. Compile and run the program and see what it does.2. Write some code that does pointer arithmetic with a pointer to an int anddetermine how big an int is.3. Same idea – figure out how big a double is, by using pointer arithmetic andprinting out the value of the pointer before and after adding 1.4. What should happen if you added 2 to the pointers from exercises 1through 3, instead of 1? Use your program to verify your answer.The program below uses pointer arithmetic to determine the size of a 'char'variable. By using pointer arithmetic we can find out the value of 'cp' and thevalue of 'cp+1'. Since cp is a pointer, this addition involves pointer arithmetic:adding one to a pointer makes the pointer point to the next element of the sametype.For a pointer to a char, adding 1 really just means adding 1 to the address, butthis is only because each char is 1 byte.1. Compile and run the program and see what it does.2. Write some code that does pointer arithmetic with a pointer to an int anddetermine how big an int is.3. Same idea – figure out how big a double is, by using pointer arithmetic andprinting out the value of the pointer before and after adding 1.4. What should happen if you added 2 to the pointers from exercises 1through 3, instead of 1? Use your program to verify your answer.#include <stdio.h>int main( ){ char c = 'Z'; char *cp = &c; printf("cp is %p\n", cp); printf("The character at cp is…Given the declaration below, if array aData[][] was associated to the memory location 1010 (in decimal), what is the value/address (in decimal) equivalent to aData[5] ? double aData[6][4]; Note that sizeof(double) results to 8, meaning 8 bytes.
- Type the SEU shortcut to do the following: Copy 3 lines from Top to Bottom Deleting last line Repeat 5 lines in the middle Exclude 5 lines Move 5 lines as a blockPLEASE MODIFY THE BELOW CODE BY USING INTERRUPTS. #include <iostream>#include <cstdlib>#include <time.h>#include <chrono>#include <pthread.h> using namespace std::chrono;using namespace std;#define NUM_THREADS 40 struct AddTask{int *v1,*v2,*v3;int start;int end;}; void randomVector(int vector[], int size){for (int i = 0; i < size; i++){ vector[i] = rand() % 100;}} void *AddVector(void* arg){ AddTask *task = (struct AddTask *) arg; for(int i = task->start; i< task->end ; i++){task->v3[i] = task->v2[i] + task->v1[i];}} int main(void){ pthread_t threads[NUM_THREADS]; unsigned long size = 100000000; srand(time(0)); int *v1, *v2, *v3; auto start = high_resolution_clock::now(); v1 = (int *) malloc(size * sizeof(int *));v2 = (int *) malloc(size * sizeof(int *));v3 = (int *) malloc(size * sizeof(int *)); randomVector(v1, size); randomVector(v2, size); for (size_t i = 0; i < NUM_THREADS; i++) {struct AddTask *task = (struct…Using only getchar from stdio.h along with the standard operators, create a program in c language where: -Initialize a multidimensional array words, where the size of the first dimension is MAXWORDS and the size of the second dimension is MAXLEN. -Write lines of code which takes an input stream of characters (max of 1000 characteres) from the user using getchar, until the user triggers the end of file.-Create three arrays of pointers p1[], p2[], p3[], where each element of these arrays point to a string.