Type your question here A 4-pole 400 V, 50 Hz wound-rotor induction motor has the following circuit model parameters: R1= 0.3 ohm R2' = 0.25 ohm, X1= X2' = 0.6 ohm , Xo = 35 ohm and rotational loss of 1500 W ( Ro is negligible). When the motor running at 1425 rpm, calculate a) the motor efficiency and, b) the maximum gross power when exciting circuit is omitted. Q1// A 4-pole ,400 V, 50 Hz wound-rotor induction motor has the following circuitmodel parameters: R¡ = 0.3 N, R¿' = 0.25 Q, X¡ = X;' = 0.6 N , Xo = 35 N androtational loss of 1500 W ( Ro is negligible) . When the motor running at 1425 rpm,calculate a) the motor efficiency and, b) the maximum gross power when exciting circuitis omitted.%3D

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Type your question here A 4-pole 400 V, 50 Hz wound-rotor induction motor has the following circuit model parameters: R1= 0.3 ohm R2' = 0.25 ohm, X1= X2' = 0.6 ohm , Xo = 35 ohm and rotational loss of 1500 W ( Ro is negligible). When the motor running at 1425 rpm, calculate a) the motor efficiency and, b) the maximum gross power when exciting circuit is omitted.

Type your question here A 4-pole 400 V, 50 Hz wound-rotor induction motor has the following circuit model parameters: R1= 0.3 ohm R2' = 0.25 ohm, X1= X2' = 0.6 ohm , Xo = 35 ohm and rotational loss of 1500 W ( Ro is negligible). When the motor running at 1425 rpm, calculate a) the motor efficiency and, b) the maximum gross power when exciting circuit is omitted.

Delmar's Standard Textbook Of Electricity

7th Edition

ISBN:9781337900348

Author:Stephen L. Herman

Publisher:Stephen L. Herman

Chapter32: Three-phase Motors

Section: Chapter Questions

Problem 13RQ: A squirrel-cage induction motor is operating at 1175 RPM and producing a torque of 22 Ib-ft. What is...

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A 4-pole ,400 V, 50 Hz wound-rotor induction motor has the following circuit model parameters: R = 0.3 2, R2 = 0.25 2, X X2' 0.6 2, Xo 35 2 and rotational loss of 1500 W ( Ro is negligible). When the motor running at 1425 rpm, %3D %3D %3D %3D calculate a) the motor efficiency and, b) the maximum gross power when exciting circuit is omitted.
A 209-V, three-phase, six-pole, Y-connected induction motor has the following parameters: R1 = 0.128 Ω, R’2 = 0.0935 Ω, Xeq =0.49Ω. The motor slip at full load is 2%. Assume that the motor load is a fan-type. If an external resistance equal to the rotor resistance is added to the rotor circuit, calculate the following: a. If the voltage is reduced by 20%, calculate the Motor speed, Starting torque, Starting current, and Motor efficiency (ignore rotational and core losses) b. If the supply frequency is reduced by 20%, calculate the Motor speed, Starting torque, Starting current, and Motor efficiency (ignore rotational and core losses)
A 209-V, three-phase, six-pole, Y-connected induction motor has the following parameters: R1 = 0.128 Ω, R’2 = 0.0935 Ω, Xeq =0.49Ω. The motor slip at full load is 2%. Assume that the motor load is a fan-type. If an external resistance equal to the rotor resistance is added to the rotor circuit, calculate the following: a. Motor speed, Starting torque, Starting current, and Motor efficiency (ignore rotational and core losses) b. Calculate the value of the resistance that should be added to the rotor circuit to reduce the speed at full load by 20%. Find the motor efficiency. c. If the voltage is reduced by 20%, calculate the Motor speed, Starting torque, Starting current, and Motor efficiency (ignore rotational and core losses) d. If the supply frequency is reduced by 20%, calculate the Motor speed, Starting torque, Starting current, and Motor efficiency (ignore rotational and core losses) ..
Equivalent circuit parameters of 3 HP (HP) 220V, 50Hz, 6 poles, split phase wound induction motor are given below. The loss of the motor is = 4W. Since the slip is s=5%; Calculate the stator current, output torque, motor speed and efficiency. R1 = 2 , R2` = 3 , X1=0 , X2` =0 , Xm=∞
A single-phase, six-pole, capacitor start, 120V/60Hz induction motor, has the following parameters:R1=1.48Ω R2=3.2 ΩX1=2.05 Ω X2=1.6 ΩThe core losses are negligible, while the friction and windage losses are constant Pf,wi=20W. The motor is operating at the rated voltage and frequency with its starting winding open, and the motor’s slip is 4.5%. Calculate:a) Stator current and power factor of the machineb) Developed electromechanical torque and the load torquec) The motor efficiency
A single phase induction motor has the following parameters:R1= 2.2Ω; X1= 3.0Ω; R’2 = 3.8Ω; X’2 = 2.1Ω; Xm = 86Ω. The motor runs at: 230V, 50 Hz, and the number of poles is 4-pole, Calculate the input current and power when the motor is operating at full-load speed of 1410 rpm. If the mechanical losses (iron and friction loss) are 60 W, determine gross power developed, the power at the shaft, shaft torque and efficiency
A three - phase, 460V, 60HZ, 4 - pole Y - connected induction motor has the following equivalent circuit parameters: Rs = 0.420, R = 0.230, X, = X =0.820, and Xm = 220. The no - load loss Pioss = 60W, assumed as a constant. The rotor speed is 1750 rpm. Determine (i) the developed power, and (ii) the efficiency
A 3-phase, 4-pole, 50-Hz induction motor has a star-connected rotor. The voltage of each rotor phase at standstill and on open-circuit is 121 V. The rotor resistance per phase is 0.3 Ω and the reactance at standstill is 0.8 Ω. If the rotor current is 15 A, calculate the speed at which the motor is running. Also, calculate the speed at which the torque is a maximum and the corresponding value of the input power to the motor, assuming the flux to remain constant.
A 208-V, two-pole, 60-Hz Y-connected wound-rotor induction motor is rated at 15 hp. Its equivalent circuit components and power losses are: R1 =0.200 Ω, R2 =0.120 Ω, X1 =0.410 Ω, X2 =0.410 Ω, XM =15.0 Ω PF&W = 250 W, Pstray = 0, Pcore = 180W For a slip of 0.05, find The stator current (I1) The stator copper losses (PSCL) The air-gap power (PAG) The power converted from electrical to mechanical (Pconv) The induced torque (τind) The load torque (τload) The overall machine efficiency The motor speed in revolutions per minute and radians per second.
381 V, four pole, 50 Hz, Y connected, to an asynchronous motor with a nominal power of 13.8 HP The corresponding equivalent circuit parameters are given below. R 1 = 0.15 Ω, R′2 = 0.154 Ω, Xm = 20 Ω, X′σ1 = 0.852 Ω, X′σ2 = 1.066 Ω It is calculated as Pstme = 390 W and Piron = 600 W for operation at label values. There is a load moment of 34 Nm on the motor shaft. Accordingly, the friction loss remains constant; a. The power transferred to the load when the motor is fed with a voltage of 50 Hz 4.16 is kW I. Draw the simplified T-equivalent circuit, not given in the circuit Calculate if there are parameters. ii. Calculate the phase current and phase voltage for the given operating condition. iii. Calculate the efficiency of the engine. iv. Calculate the tipping moment and tipping slip.
A 440V, 60Hz, 10 pole delta connected induction motor is rated at 100KW. The equivalent parameter for the motor are: Rs = 0.15 Ω R2` = 0.15 Ω Xs = 0.3 Ω X2` = 0.2 Ω Xm = 6 Ω R c = 120 Ω At full load condition, the friction and windage losses are 600W. The slip of the motor is 0.04. Calculate: The stator line current Is ? The input power ? Stator copper losses ? The air gap power PG ? The converted power Pconv? The torque induced by the motor ? The load torque ? The starting torque? The efficiency of the motor ?
A 3-phase, 6-pole and 50Hz induction motor has a speed of 955d/min under full load, a torque of 120 N.m and a current of 20 A. Under rated voltage, the starting current is 100A. Accordingly, which of the following is the starting torque of the motor?a) 120N.mb) 150N.mc) 144N.md) 135N.me) 156N.m