(U) A blanking die must be designed to blank the part outline shown in Figure 4 jall dimensions in mm). The material is 4-mm-thick stainless steel (half hard). Determine the (a) dimensions of the blanking punch and the die opening and (b) cutting force required, given that the stainless steel has a yleld strength = 275 MPa, shear strength = 450 MPa, and tensile strength = 650 MPa. Metal Group 1100S and 50525 aluminum alloys, all sempers. 2024ST and 6061ST aluminum allays; brass, all tempers; saft cold-rolled steel, soft stainless steel. 0.045 0.060 Cold-rolled steel, half hard; stainless steel, half-hard and full-hard. 0.075 Tompiled fam (3 60 10 15

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
icon
Related questions
Question
100%
Correct and complete solution please don't copy
(u) A blanking die must be designed to blank the part outline shown in Figure 4 (all dimensions in
mm). The material is 4-mm-thick stainless steel (half hard). Determine the (a) dimensians of the
blanking punch and the die opening and (b) cutting force required, given that the stainless steel
has a yleld strength = 275 MPa, shear strength = 450 MPa, and tensile strength = 650 MPa.
Metal Group
1100S and 50525 aluminum alloys, all tempers.
0.045
2024ST and 6061ST aluminum allays; brass, all tempers; soft cold-rolled steel, soft
stainless steel.
0.060
Cold-rolled steel, half hard; stainless steel, half-hard and full-hard.
0.075
Compited fam (31
60
20
10
Figure 4: 04 ()
Transcribed Image Text:(u) A blanking die must be designed to blank the part outline shown in Figure 4 (all dimensions in mm). The material is 4-mm-thick stainless steel (half hard). Determine the (a) dimensians of the blanking punch and the die opening and (b) cutting force required, given that the stainless steel has a yleld strength = 275 MPa, shear strength = 450 MPa, and tensile strength = 650 MPa. Metal Group 1100S and 50525 aluminum alloys, all tempers. 0.045 2024ST and 6061ST aluminum allays; brass, all tempers; soft cold-rolled steel, soft stainless steel. 0.060 Cold-rolled steel, half hard; stainless steel, half-hard and full-hard. 0.075 Compited fam (31 60 20 10 Figure 4: 04 ()
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Knowledge Booster
Entropy
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Elements Of Electromagnetics
Elements Of Electromagnetics
Mechanical Engineering
ISBN:
9780190698614
Author:
Sadiku, Matthew N. O.
Publisher:
Oxford University Press
Mechanics of Materials (10th Edition)
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:
9780134319650
Author:
Russell C. Hibbeler
Publisher:
PEARSON
Thermodynamics: An Engineering Approach
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:
9781259822674
Author:
Yunus A. Cengel Dr., Michael A. Boles
Publisher:
McGraw-Hill Education
Control Systems Engineering
Control Systems Engineering
Mechanical Engineering
ISBN:
9781118170519
Author:
Norman S. Nise
Publisher:
WILEY
Mechanics of Materials (MindTap Course List)
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:
9781337093347
Author:
Barry J. Goodno, James M. Gere
Publisher:
Cengage Learning
Engineering Mechanics: Statics
Engineering Mechanics: Statics
Mechanical Engineering
ISBN:
9781118807330
Author:
James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:
WILEY