Ultimately, we wish to find the solution(s) to the following system of equations. 4x - 5y = 15 0.8x y = -3 First, we will graph each equation by hand using the slope-intercept form of an equation, y = mx + b, where y is the dependent variable and x is the independent variable. Write the first equation in slope-intercept form. 4x - 5y = 15 - 5y = y = x- Write the second equation in slope-intercept form. 0.8x - y = -3 -y = y = y = + 15 5 3 x + 3 +3

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter9: Quadratic Functions And Equations
Section9.7: Solving Systems Of Linear And Quadratic Equations
Problem 30HP
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Write the first equation in slope-intercept form

writr the second equation in slope-intercept form

Ultimately, we wish to find the solution (s) to the following system of equations.
4x - 5y = 15
0.8x – y = -3
First, we will graph each equation by hand using the slope-intercept form of an equation, y = mx + b, where y is the
dependent variable and x is the independent variable.
Write the first equation in slope-intercept form.
4x - 5y = 15
- 5y =
y =
-y =
y =
4
Write the second equation in slope-intercept form.
0.8x y = -3
y =
x + =
5
+ 15
- 3
x + 3
x + 3
Transcribed Image Text:Ultimately, we wish to find the solution (s) to the following system of equations. 4x - 5y = 15 0.8x – y = -3 First, we will graph each equation by hand using the slope-intercept form of an equation, y = mx + b, where y is the dependent variable and x is the independent variable. Write the first equation in slope-intercept form. 4x - 5y = 15 - 5y = y = -y = y = 4 Write the second equation in slope-intercept form. 0.8x y = -3 y = x + = 5 + 15 - 3 x + 3 x + 3
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