Upon multiplication by -3x-4 and using the substitution Z= X¯³, dz= - 3x-4dx, the Bernoulli's DE dx - x cot y= xªcsc²y reduces to dy A + 3zcot y = - 3csc?y dy dz B 3zcot y = 3csc²y dy dz + 3zcot y = 3csc?y dy dz 3zcot y = - 3csc?y dy B.
Upon multiplication by -3x-4 and using the substitution Z= X¯³, dz= - 3x-4dx, the Bernoulli's DE dx - x cot y= xªcsc²y reduces to dy A + 3zcot y = - 3csc?y dy dz B 3zcot y = 3csc²y dy dz + 3zcot y = 3csc?y dy dz 3zcot y = - 3csc?y dy B.
Algebra for College Students
10th Edition
ISBN:9781285195780
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter13: Conic Sections
Section13.1: Circles
Problem 48PS
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