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When reduced to a linear DE of order one in z, the Bernoulli's equation dy 2 +y √( 1 ) = 3x²y² = 3x²y² becomes dx X A B C dz dx dz dx dz +z =)= X 1 (+)₁ X +z = 1 3x² 3x²

When reduced to a linear DE of order one in z, the Bernoulli's equation dy 2 +y √( 1 ) = 3x²y² = 3x²y² becomes dx X A B C dz dx dz dx dz +z =)= X 1 (+)₁ X +z = 1 3x² 3x²

College Algebra (MindTap Course List)
College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter6: Linear Systems
Section6.2: Guassian Elimination And Matrix Methods
Problem 84E: Explain the differences between Gaussian elimination and Gauss-Jordan elimination.
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When reduced to a linear DE of order one in z, the Bernoulli's equation dy ( 1 ) = 3 x ² dx X +y A B C D dz dx dz dx dz dx = 3x²y² becomes +z +z (1) X -=-= X +z = X 3x² - 3x² = 3x²
Transcribed Image Text:When reduced to a linear DE of order one in z, the Bernoulli's equation dy ( 1 ) = 3 x ² dx X +y A B C D dz dx dz dx dz dx = 3x²y² becomes +z +z (1) X -=-= X +z = X 3x² - 3x² = 3x²
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