Use ? = 0.05 to test the hypothesis that there is no difference between the median percent of on-time arrivals for the two years. State the null and alternative hypotheses. H0: Median percent on-time in 2006 − Median percent on-time in 2007 ≥ 0 Ha: Median percent on-time in 2006 − Median percent on-time in 2007 < 0H0: Median percent on-time in 2006 − Median percent on-time in 2007 ≤ 0 Ha: Median percent on-time in 2006 − Median percent on-time in 2007 > 0 H0: Median percent on-time in 2006 − Median percent on-time in 2007 > 0 Ha: Median percent on-time in 2006 − Median percent on-time in 2007 = 0H0: Median percent on-time in 2006 − Median percent on-time in 2007 ≠ 0 Ha: Median percent on-time in 2006 − Median percent on-time in 2007 = 0H0: Median percent on-time in 2006 − Median percent on-time in 2007 = 0 Ha: Median percent on-time in 2006 − Median percent on-time in 2007 ≠ 0 Find the value of the test statistic. T + = Find the p-value. (Round your answer to four decimal places.) p-value = What is your conclusion? Do not reject H0. There is sufficient evidence to conclude that there is a significant difference between the median percent of on-time arrivals for the two years.Do not reject H0. There is not sufficient evidence to conclude that there is a significant difference between the median percent of on-time arrivals for the two years. Reject H0. There is sufficient evidence to conclude that there is a significant difference between the median percent of on-time arrivals for the two years.Reject H0. There is not sufficient evidence to conclude that there is a significant difference between the median percent of on-time arrivals for the two years.
Use ? = 0.05 to test the hypothesis that there is no difference between the median percent of on-time arrivals for the two years. State the null and alternative hypotheses. H0: Median percent on-time in 2006 − Median percent on-time in 2007 ≥ 0 Ha: Median percent on-time in 2006 − Median percent on-time in 2007 < 0H0: Median percent on-time in 2006 − Median percent on-time in 2007 ≤ 0 Ha: Median percent on-time in 2006 − Median percent on-time in 2007 > 0 H0: Median percent on-time in 2006 − Median percent on-time in 2007 > 0 Ha: Median percent on-time in 2006 − Median percent on-time in 2007 = 0H0: Median percent on-time in 2006 − Median percent on-time in 2007 ≠ 0 Ha: Median percent on-time in 2006 − Median percent on-time in 2007 = 0H0: Median percent on-time in 2006 − Median percent on-time in 2007 = 0 Ha: Median percent on-time in 2006 − Median percent on-time in 2007 ≠ 0 Find the value of the test statistic. T + = Find the p-value. (Round your answer to four decimal places.) p-value = What is your conclusion? Do not reject H0. There is sufficient evidence to conclude that there is a significant difference between the median percent of on-time arrivals for the two years.Do not reject H0. There is not sufficient evidence to conclude that there is a significant difference between the median percent of on-time arrivals for the two years. Reject H0. There is sufficient evidence to conclude that there is a significant difference between the median percent of on-time arrivals for the two years.Reject H0. There is not sufficient evidence to conclude that there is a significant difference between the median percent of on-time arrivals for the two years.
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.4: Distributions Of Data
Problem 19PFA
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In this exercise involving paired differences, consider that it is reasonable to assume the populations being compared have approximately the same shape and that the distribution of paired differences is approximately symmetric.
Percents of on-time arrivals for flights in 2006 and 2007 were collected for 11 randomly selected airports. Suppose data for these airports follow.
Airport | Percent On-Time | ||
---|---|---|---|
2006- | 2007 | ||
1 | 71.78 | 68.69 | |
2 | 68.23 | 65.88 | |
3 | 76.98 | 78.40 | |
4 | 78.71 | 75.78 | |
5 | 78.59 | 72.45 | |
6 | 78.67 | 79.68 | |
7 | 75.67 | 77.38 | |
8 | 75.29 | 69.98 | |
9 | 68.39 | 62.84 | |
10 | 80.91 | 77.49 | |
11 | 76.55 | 71.42 |
Use ? = 0.05 to test the hypothesis that there is no difference between the median percent of on-time arrivals for the two years.
State the null and alternative hypotheses.
H0: Median percent on-time in 2006 − Median percent on-time in 2007 ≥ 0
Ha: Median percent on-time in 2006 − Median percent on-time in 2007 < 0H0: Median percent on-time in 2006 − Median percent on-time in 2007 ≤ 0
Ha: Median percent on-time in 2006 − Median percent on-time in 2007 > 0 H0: Median percent on-time in 2006 − Median percent on-time in 2007 > 0
Ha: Median percent on-time in 2006 − Median percent on-time in 2007 = 0H0: Median percent on-time in 2006 − Median percent on-time in 2007 ≠ 0
Ha: Median percent on-time in 2006 − Median percent on-time in 2007 = 0H0: Median percent on-time in 2006 − Median percent on-time in 2007 = 0
Ha: Median percent on-time in 2006 − Median percent on-time in 2007 ≠ 0
Ha: Median percent on-time in 2006 − Median percent on-time in 2007 < 0H0: Median percent on-time in 2006 − Median percent on-time in 2007 ≤ 0
Ha: Median percent on-time in 2006 − Median percent on-time in 2007 > 0 H0: Median percent on-time in 2006 − Median percent on-time in 2007 > 0
Ha: Median percent on-time in 2006 − Median percent on-time in 2007 = 0H0: Median percent on-time in 2006 − Median percent on-time in 2007 ≠ 0
Ha: Median percent on-time in 2006 − Median percent on-time in 2007 = 0H0: Median percent on-time in 2006 − Median percent on-time in 2007 = 0
Ha: Median percent on-time in 2006 − Median percent on-time in 2007 ≠ 0
Find the value of the test statistic.
T + =
Find the p-value. (Round your answer to four decimal places.)
p-value =
What is your conclusion?
Do not reject H0. There is sufficient evidence to conclude that there is a significant difference between the median percent of on-time arrivals for the two years.Do not reject H0. There is not sufficient evidence to conclude that there is a significant difference between the median percent of on-time arrivals for the two years. Reject H0. There is sufficient evidence to conclude that there is a significant difference between the median percent of on-time arrivals for the two years.Reject H0. There is not sufficient evidence to conclude that there is a significant difference between the median percent of on-time arrivals for the two years.
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