Use a Standard normal distribution table to find the percent of the total under the standard normal curve between the following Z scores. Z equals 0.5 and z equals 1.2The percent of the total area between Z equals 0.55 and see equal 1.2 is %(Round to the nearest integer) Section 14.4- The Normal DistributionThe normal distribution (normal curve) is a way to study data using the information you.ave learned about. A normal distribution is a bell shaped curve that is symmetric withrespect to the mean. A normal distribution usually applies to a whole population, not asample, therefore the mean is now called u (mu).)34%34%115815-62.35%-30-20-10-35D -25D ISD13.5%m68%95%99.7%13.5%+1oSD+202.35%+30SD z - Score Table0.070.0820.050.0600.010.020.040.03531885279052392+05199450000 503995079851595511975714256749+0.1563605398355966.54380.54776555675517261026.60642+0.257926602575987158317.58706594835909564431.64803+0.3617916405863683.62172.625526330762930.6808268439+0.4.67724.65542 .65910.67364.66276.66640.67003.71566.71904+0.5.7122669146 69497.69847.70884.70194.7054074857.75175+0.6.72575.74537.72907 .73237.74215.73565.73891.78230+0.7.77935.75804 .76115.77637.76424.76730.77337.77035+0.8810578078580511.78814 .79103.79389.79673.799558023483646+0.98339881594 .818598212183147.823818263982894+1857698554385993.8413484849853148508388100+1.1.86433 .86650.84375 .84614.86864 .87076.88877 .89065 .8925187900872868749387698+1.28849389973.88686894358961789796+1.39032091621.9049090658.90824 9098891149 91308.91466+1.491924.920739305692220.92364 9250792647.92785.92922+1.5.93319.93448.9357493822.93699.93943.94062.9417994295+1.69452094630.94738.9495095053951549525495352+1.7 .9554396164 .96246+1.895637 9572896407 .9648597128 .971939484595818 .9590796638 .96712.97320 9738197932.95994 .96080.96784 .96856 .96926 .9699596562+1.997257.97441 .97500 97558.97615+297725.97778978319788297982.9803098077.98124+2.198214 98257 .983009834198382.98422.9846198500 .98537+2.298713.9874598778988099884098870+2.39867998983 .99010.9924599036.9906198610 9864598928 .98956.99180.99379 .99396.9908699111.99134+2.49926699286.993059932499343+2.5.99446.99461 .99477 .99492.99413 99430.9957399506+2.69958599598996099962199632+2.7.99653 .99664.99534 .99547 99560.99674.99752 .99760.99683996939970299711.9972099728+2.89974499767 .9977499781997889979599801+2.9.9981399819.99825.99831 .99836.99841 .998469985199856+399865.9986999874 99878998829988699889.9989399896+3.1 .99903.99906999169991899921.9992499926+3.2 .99931.99940 .99942999449994699948+3.399960 .99961.9996299964+3.4999739997499975+3.599910 .999139993499936 9993899952 .99953 .99955 .99957 99958.99966 99968 99969 .99970 .99971 99972.99977 .99978 .99978 .99979 .99980 .99981.99984 99985 .99985 99986 99986 .9998799989 99990 99990.99991+3.899993 .99993+3.9 .99995 99995+49998199982 99983+3.6999879998899988+3.799992.99990 .99991.99993 .99994 99994.99992 99992999949999499995 99995.99996 .99996 999969999699996 999969999799997 .99997 99997 999979999799997999989999899998.99202 992240.09535865753561409.65173.68793.72240.75490.78524813278389186214.88298)901479177493189.9440895449.9632797062.97670.981699857498899.99158.99361.99520996439973699807.99861.9990099929999509996599976999839998999992999959999799998

Question

Use a Standard normal distribution table to find the percent of the total under the standard normal curve between the following Z scores. Z equals 0.5  and z equals 1.2￼The percent of the total area between Z equals 0.55 and see equal 1.2 is  %(Round to the nearest integer)￼ Section 14.4- The Normal DistributionThe normal distribution (normal curve) is a way to study data using the information you.ave learned about. A normal distribution is a bell shaped curve that is symmetric withrespect to the mean. A normal distribution usually applies to a whole population, not asample, therefore the mean is now called u (mu).)34%34%115815-62.35%-30-20-10-35D -25D ISD13.5%m68%95%99.7%13.5%+1oSD+202.35%+30SD z - Score Table0.070.0820.050.0600.010.020.040.03531885279052392+05199450000 503995079851595511975714256749+0.1563605398355966.54380.54776555675517261026.60642+0.257926602575987158317.58706594835909564431.64803+0.3617916405863683.62172.625526330762930.6808268439+0.4.67724.65542 .65910.67364.66276.66640.67003.71566.71904+0.5.7122669146 69497.69847.70884.70194.7054074857.75175+0.6.72575.74537.72907 .73237.74215.73565.73891.78230+0.7.77935.75804 .76115.77637.76424.76730.77337.77035+0.8810578078580511.78814 .79103.79389.79673.799558023483646+0.98339881594 .818598212183147.823818263982894+1857698554385993.8413484849853148508388100+1.1.86433 .86650.84375 .84614.86864 .87076.88877 .89065 .8925187900872868749387698+1.28849389973.88686894358961789796+1.39032091621.9049090658.90824 9098891149 91308.91466+1.491924.920739305692220.92364 9250792647.92785.92922+1.5.93319.93448.9357493822.93699.93943.94062.9417994295+1.69452094630.94738.9495095053951549525495352+1.7 .9554396164 .96246+1.895637 9572896407 .9648597128 .971939484595818 .9590796638 .96712.97320 9738197932.95994 .96080.96784 .96856 .96926 .9699596562+1.997257.97441 .97500 97558.97615+297725.97778978319788297982.9803098077.98124+2.198214 98257 .983009834198382.98422.9846198500 .98537+2.298713.9874598778988099884098870+2.39867998983 .99010.9924599036.9906198610 9864598928 .98956.99180.99379 .99396.9908699111.99134+2.49926699286.993059932499343+2.5.99446.99461 .99477 .99492.99413 99430.9957399506+2.69958599598996099962199632+2.7.99653 .99664.99534 .99547 99560.99674.99752 .99760.99683996939970299711.9972099728+2.89974499767 .9977499781997889979599801+2.9.9981399819.99825.99831 .99836.99841 .998469985199856+399865.9986999874 99878998829988699889.9989399896+3.1 .99903.99906999169991899921.9992499926+3.2 .99931.99940 .99942999449994699948+3.399960 .99961.9996299964+3.4999739997499975+3.599910 .999139993499936 9993899952 .99953 .99955 .99957 99958.99966 99968 99969 .99970 .99971 99972.99977 .99978 .99978 .99979 .99980 .99981.99984 99985 .99985 99986 99986 .9998799989 99990 99990.99991+3.899993 .99993+3.9 .99995 99995+49998199982 99983+3.6999879998899988+3.799992.99990 .99991.99993 .99994 99994.99992 99992999949999499995 99995.99996 .99996 999969999699996 999969999799997 .99997 99997 999979999799997999989999899998.99202 992240.09535865753561409.65173.68793.72240.75490.78524813278389186214.88298)901479177493189.9440895449.9632797062.97670.981699857498899.99158.99361.99520996439973699807.99861.9990099929999509996599976999839998999992999959999799998

Accepted Answer

GivenThe percent of the total under the standard normal curve between 0.5 and 1.2

Use a Standard normal distribution table to find the percent of the total under the standard normal curve between the following Z scores. Z equals 0.5 and z equals 1.2￼ The percent of the total area between Z equals 0.55 and see equal 1.2 is % (Round to the nearest integer)￼

Use a Standard normal distribution table to find the percent of the total under the standard normal curve between the following Z scores. Z equals 0.5 and z equals 1.2 The percent of the total area between Z equals 0.55 and see equal 1.2 is % (Round to the nearest integer)