Use the conversion factors:I-748gullon60 min=1 hrI psi = 6869.491 PaConvert the units.60 f'min "Rpsigallon hr "KPaA60 f'min "R1 hrpsi60 ain1.8 "RI psix 7.48 gallom6869.491 PaB60 min "R60 hr x 18 "K xpsiI min6869.491 psi x I gallonI Pa7.48 f60 f min "R x I min x1'R xpsi60 hr1.8 "K6869.491 psi x 7.481 PaI gullonLTE .9:19wala-Ims1paaet adu.kwD60 f min "R x 60 min x 1.8 "R x1 hrpsi1°KI psi1 fe6869.491 Pa7.48 gallonThe correct answer isBC

Answered: Image /qna-images/answer/b0e5aab6-bd3f-4759-ae1c-ca26e99e43d7.jpg

Answered: Use the conversion factors: IP-748…

Use the conversion factors: IP-748 gullon 60 min=I hr I psi - 6869.491 Pa Convert the units. 60 min "R pi gallon hr "K Pa 60 t'min "R x psi I hr x 1'K 60 min L8 "R I psi x 7.48 gallon 6R69.491 Pe B.

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter28: Current And Resistance

Section: Chapter Questions

Problem 58PQ

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Estimate of calculation

Question

Use the conversion factors:
I-748
gullon
60 min=1 hr
I psi = 6869.491 Pa
Convert the units.
60 f'min "R
psi
gallon hr "K
Pa
A
60 f'min "R
1 hr
psi
60 ain
1.8 "R
I psi
x 7.48 gallom
6869.491 Pa
B
60 min "R
60 hr x 18 "K x
psi
I min
6869.491 psi x I gallon
I Pa
7.48 f
60 f min "R x I min x
1'R x
psi
60 hr
1.8 "K
6869.491 psi x 7.48
1 Pa
I gullon
LTE .
9:19
wala-
Ims1paaet adu.kw
D
60 f min "R x 60 min x 1.8 "R x
1 hr
psi
1°K
I psi
1 fe
6869.491 Pa
7.48 gallon
The correct answer is
B
C

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