Use the dynamic points to graph the polynomial = x (2² – 1). Since p(-x) = -p(x) for all real 2, we know that p(x) is an odd function. The fixed points represent points of interest: x-intercepts, relative extrema, and inflection points. NOTE: Do not try to position a dynamic point at (0,0), as that point has already been graphed for you. %3D (1.3,0.7) (0.4,0.2) (-1,0) 1,0) 0.2)

College Algebra
1st Edition
ISBN:9781938168383
Author:Jay Abramson
Publisher:Jay Abramson
Chapter5: Polynomial And Rational Functions
Section5.3: Graphs Of Polynomial Functions
Problem 2TI: Use the graph of the function of degree 5 in Figure 10 to identify the zeros of the function and...
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Can you graph this? I hope you will plot 5 points without (0,0) point. Please be exact with the decimal of the points. Thank you.
UI App
i education.wiley.com
22
Question 3 of 11
Use the dynamic points to graph the polynomial
(02 – 1). Since p(-x) = -p(x) for all real », we know
p(a) =
that p(x) is an odd function. The fixed points represent points
of interest: x-intercepts, relative extrema, and inflection points.
NOTE: Do not try to position a dynamic point at (0,0), as that point has already been
graphed for you.
1.
(1.3, 0.7)
(0.4,0.2)
-1,0)
1,0)
04,-0.2)
here to search
Transcribed Image Text:UI App i education.wiley.com 22 Question 3 of 11 Use the dynamic points to graph the polynomial (02 – 1). Since p(-x) = -p(x) for all real », we know p(a) = that p(x) is an odd function. The fixed points represent points of interest: x-intercepts, relative extrema, and inflection points. NOTE: Do not try to position a dynamic point at (0,0), as that point has already been graphed for you. 1. (1.3, 0.7) (0.4,0.2) -1,0) 1,0) 04,-0.2) here to search
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