Use the figure below to answer the corresponding question. A 100 um 50 μη Z00 um 100 um Which of the following statements about Figure 4-1 is true? O Figure B has a greater surface area than Figure A. O Figure B has a greater volume than Figure A. O Figure B has a smaller volume than Figure A. O Figure B has a greater surface area to volume ratio than Figure A. O Figure B has a smaller surface area to volume ratio than Figure A.

Aquaculture Science
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ISBN:9781133558347
Author:Parker
Publisher:Parker
Chapter14: Aquariums
Section: Chapter Questions
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Use the figure below to answer the corresponding question.
B.
100 pm
100 um
100pm
Which of the following statements about Figure 4-1 is true?
O Figure B has a greater surface area than Figure A.
O Figure B has a greater volume than Figure A.
Figure B has a smaller volume than Figure A.
O Figure B has a greater surface area to volume ratio than Figure A.
Figure B has a smaller surface area to volume ratio than Figure A.
Transcribed Image Text:Use the figure below to answer the corresponding question. B. 100 pm 100 um 100pm Which of the following statements about Figure 4-1 is true? O Figure B has a greater surface area than Figure A. O Figure B has a greater volume than Figure A. Figure B has a smaller volume than Figure A. O Figure B has a greater surface area to volume ratio than Figure A. Figure B has a smaller surface area to volume ratio than Figure A.
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Step 1

In the figure A there are total 8 cells. The volume of each cell is (50×50×50)umand total volume of 8 cells = 8×(50×50×50)um3 = 1000000 um3 and surface area is high as there are more than 1 cells are present. Surface area of 1 cell = 6×(50×50) = 15000 um2. So, total surface area for 8 cells = (8×15000) = 120000 um2.

In the figure B the one big cell is present and the volume is (100×100×100)um3 = 1000000 um3 and surface area is low as only a single cell is present. The surface area is = 6×(100×100) = 60000 um2.

So, the surface are to volume ratio in case of figure A is (120000÷1000000)= 0.12

The surface area to volume ratio in case of figure B is (60000÷1000000) = 0.06

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