Use the first derivative to find all critical points and use the second derivative to find all inflection points. Use a graph to identify each critical point as a local maximum, a local minimum, or neither. f (x) = 2x + 3² – 180x + 6 Enter the exact answers in increasing order. If there is no answer, enter "NA". The critical point at x = is The critical point at x = is The inflection point is x = |

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section: Chapter Questions
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Chapter 4, Section 4.2, Question 014
Use the first derivative to find all critical points and use the second derivative to find all inflection points. Use a graph to identify each critical point as a local maximum, a local minimum, or neither.
f (x) = 2x + 3x² – 180x + 6
Enter the exact answers in increasing order. If there is no answer, enter "NA".
The critical point at x =
is
The critical point at x =
is
The inflection point is x =
Click if you would like to Show Work for this question: Open Show Work
Transcribed Image Text:Chapter 4, Section 4.2, Question 014 Use the first derivative to find all critical points and use the second derivative to find all inflection points. Use a graph to identify each critical point as a local maximum, a local minimum, or neither. f (x) = 2x + 3x² – 180x + 6 Enter the exact answers in increasing order. If there is no answer, enter "NA". The critical point at x = is The critical point at x = is The inflection point is x = Click if you would like to Show Work for this question: Open Show Work
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