Use the given values to find k. We are told that 250 cubic centimeters of snow will melt to 28 cubic centimeters of water. Substitute 28 for W and 250 for S in the direct variation equation. Then solve for k. W = kS Volume of water varies directly as volume of melting snow. 28 = k(250) 250 cubic centimeters of snow melt to 28 cubic centimeters of water. 28 k(250) Divide both sides by 250. 250 250 0.112 = k Simplify.

Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter8: Introduction To Functions
Section8.9: Direct Variation
Problem 15P
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Use the given values to find k. We are told that 250 cubic centimeters of
snow will melt to 28 cubic centimeters of water. Substitute 28 for W and 250 for S in the
direct variation equation. Then solve for k.
W = kS
Volume of water varies directly as volume of
melting snow.
28 = k(250)
250 cubic centimeters of snow melt to
28 cubic centimeters of water.
28
k(250)
Divide both sides by 250.
250
250
0.112 = k
Simplify.
Transcribed Image Text:Use the given values to find k. We are told that 250 cubic centimeters of snow will melt to 28 cubic centimeters of water. Substitute 28 for W and 250 for S in the direct variation equation. Then solve for k. W = kS Volume of water varies directly as volume of melting snow. 28 = k(250) 250 cubic centimeters of snow melt to 28 cubic centimeters of water. 28 k(250) Divide both sides by 250. 250 250 0.112 = k Simplify.
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