Use the half reaction for pyruvate oxidation to compute the following at 25 °C. CH,COCOO-(pyruvate) + 4H₂O→ 2CO₂+HCO3 + 10H++ 10e a. Compute AG in kJ/mole pyruvate. b. Compute AG in kJ/mole pyruvate.
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- Oxidation of lactate by cytochrome C (represented as cytochrome C (Fe3 +)) to pyruvate is an important biological reaction.Below are the reduction reactions and standard reduction potentials (E °) at pH = 7 and 25 ° C.Pyruvate + 2H + + 2e- = Lactate - (E ° = -0.185 V)Cytochrome C (Fe3 +) + e - = Cytochrome C (Fe2 +) (E ° = 0.254 V)Write the anodic, cathodic, and total reactions.Show that the oxidation of Cl- to Cl2(g) by Cr2O72- in acidic solution will NOT occur with reactants and products in their standard states. If, however, this is to be used for the production of Cl2 in the laboratory, how would you go about it?Reaction : Cl2 + H2O <-> HClO + H+ + Cl- Half; Cl2 + 2e- -> 2Cl- E*cell = 1.36V HClO + H+ +2e- -> H2O E*cell = 1.49V Ecell = -0.13V Question: Using the Nernst Equation, determine if the reaction in question 10 is spontaneous at 20 °C with concentrations 0.1 M for each. Explain your answer. I found other answers but I couldn't understand why Q is [H+][Cl-]/1
- The battery Pt|H2(1 atm)|HBr(aq)|AgBr(s)|Ag| pt At 25°C, with HBr molality 0.1000 mol/kg has ε = 0.200 V. Find the coefficient of mean ionic activity of HBr(aq) at this molality.Write the overall reaction of the cell and indicate the species that is oxidized and the one that is reduce.Given the reaction: Anode: NO3- + 2H + +e- ---> NO2 + H2O Cathode: 2H + 2e- ---> H2 Redox: 2NO2(g) + 2H2O(l) ---> 2NO3-(aq) + 2H + (aq) + H2(g) Given conditions: [0.15 atm] [0.18atm] [0.1 M] [0.67atm] a. Find the standard cell potential, Eocell? b. Calculate the cell potential, Ecell? c. Calculate the pH, if Ecell = -0.70 Vassume that in a certain cell, the ratio of products/reactants or Keq = 778.3 (Keq is dimensionless) for the reaction Glucose + 2ATP <> Glucose-1,6-diP + 2ADP, at a particular instant, the concentrations of each compound were Glucose =3.5M, ATP =11.8M, ADP =13.4M and G-6-P =21.6M. Calculate the difference (dimensionless) between Keq and the ratio of products/ractants at this instance, in this cell, to five significant figures. Thank you for your assistance.
- Hello the aanswer of this question is wrong in the second part in your website. It is not 2.55 The standard potentials for the reduction of nicotinamide adenine dinucleotide (NAD+) and oxaloacetate (reactants in the multistep metabolism of glucose) are as follows:NAD+(aq)+2H+(aq)+2e−NADH(aq)+H+(aq) E° = –0.330 VOxaloacetate2−(aq)+2H+(aq)+2e−(aq)malate2−(aq) E° = –0.166 V Calculate the standard potential for the following reaction: Oxaloacetate2−(aq)+NADH(aq)+H+(aq)malate2−(aq)+NAD+(aq) Calculate the equilibrium constant at 298.15 K for the reaction.Calculate the standard emf, E°, for the following cell reaction from standaard free energies of formation. 2Al(s) + 3Cu2+(aq) ----> 2Al3+(aq) + 3Cu(s) Express your answer to 2 decimal places. ΔGf°(Al(s)) = 0 kJ/mol ΔGf°(Al3+(aq)) = -485 kJ/mol ΔGf°(Cu(s)) = 0 kJ/mol ΔGf°(Cu2+(aq)) = 64.98 kJ/molWhich expression(s) are incorrectly defined? I- Ohmic potential is the voltage that overcomes its electrical resistance in an electrochemical cell while current is flowing. II- Concentration polarization occurs when the concentrations of reactants or products on the electrode surface are greater than that in the whole solution. III- Overvoltage is only the voltage required to overcome the activation energy of the reaction at the cathode. cathode only. IV- E = Ekatode - Eanode - IR - overvoltage - concentration polarization A.II and IVB. I and IIC. I, II and IIID. II, III and IV
- Which expression(s) are incorrectly defined? I- Ohmic potential is the voltage that overcomes its electrical resistance in an electrochemical cell while current is flowing. II- Concentration polarization occurs when the concentrations of reactants or products on the electrode surface are greater than that in the whole solution. III- Overvoltage is only the voltage required to overcome the activation energy of the reaction at the cathode. cathode only. IV- E = Ekatode - Eanode - IR - overvoltage - concentration polarizationWhich expression(s) are incorrectly defined? I- Ohmic potential is the voltage that overcomes its electrical resistance in an electrochemical cell while current is flowing. II- Concentration polarization occurs when the concentrations of reactants or products on the electrode surface are greater than that in the whole solution. III- Overvoltage is only the voltage required to overcome the activation energy of the reaction at the cathode. cathode only. IV- E = Ekatode - Eanode - IR - overvoltage - concentration polarization A.) II and IV B.) I and II C.)I, II and III D.) II, III and IVStarting with the standard free energies of formation from the following table, calculate the values of the E°cell of the following reactions: Substance ΔΔG°f (kJ/mol) FeO(s) -255.2 H2(g) 0 Fe(s) 0 H2O(l) -237.2 Pb(s) 0 O2(g) 0 H2SO4(aq) -744.5 PbSO4(s) -813.0 2Pb(s) + O2(g) + 2H2SO4(aq) ----- > 2PbSO4(s) + 2H2O(l) E°cell = V