6) Let F(x, y, z) = 2ri+xyj+r²zk be a vector field and S the surface with equation x = In (y - 1) described in the following figure. When taking n = (e, 1, 0) then the normal vector unitary that determines the orientation of S is N = The double integral that allows to calculate the flux integral F F. Nds is: -6 5 A) [² m² (re² − x) dxdz 6 cln 5 B)(x − xe²) dxdz 0 0 -6 In 5 C) [ L™³ xez <- x √e²+1 dx dz -6 5 D) Lith (re* — a) dx dz In 5 S

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