Use the Intermediate Value Theorem to show that there is a root of the given equation in the specified interval. x+x-6-0., (1, 2) Rx)=x²+x-6 is ---Select--on the closed interval [1, 2], f(1) = and f(2)= Since -4 <12, there is a number c in (1, 2) such that fc) = ? by the Intermediate Value Theorem. Thus, there is a --Select--of the equation x²+x-6=0 in the interval (1, 2).

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.5: Rational Functions
Problem 51E
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Use the Intermediate Value Theorem to show that there is a root of the given equation in the specified interval.
+x-6= 0, (1, 2)
f(x)=x²+x-6 is ---Select--- on the closed interval [1, 2], f(1) =
and f(2)=
Since -4 < ?< 12, there is a number c in (1, 2) such that f(c) =? by the Intermediate Value Theorem. Thus, there is a
-Select---
✓of the equation x4+x-6 = 0 in the interval (1, 2).
Transcribed Image Text:Use the Intermediate Value Theorem to show that there is a root of the given equation in the specified interval. +x-6= 0, (1, 2) f(x)=x²+x-6 is ---Select--- on the closed interval [1, 2], f(1) = and f(2)= Since -4 < ?< 12, there is a number c in (1, 2) such that f(c) =? by the Intermediate Value Theorem. Thus, there is a -Select--- ✓of the equation x4+x-6 = 0 in the interval (1, 2).
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