Use the Intermediate Value Theorem to show that there is a root of the given equation in the specified interval. x4+x-7-0, (1, 2) f(x)=x²+x-7 is-Select--on the closed interval [1, 2], f(1) = , and f(2)= . Since -5 < ?< 11, there is a number c in (1, 2) such that f(c) = ? by the Intermediate Value Theorem. Thus, there is a ---Select--of the equation x4 + x - 7= 0 in the interval (1, 2).

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.2: Graphs Of Equations
Problem 78E
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Q13. Please answer all the parts to this question

Use the Intermediate Value Theorem to show that there is a root of the given equation in the specified interval.
x4 + x - 7 = 0, (1, 2)
f(x) = x² + x - 7 is ---Select---
on the closed interval [1, 2], f(1) =
, and f(2)=
Since -5<? < 11, there is a number c in (1, 2) such that f(c) = ? by the Intermediate Value Theorem. Thus, there is a ---Select--- ✓of the equation x² + x - 7 = 0 in the interval (1, 2).
Transcribed Image Text:Use the Intermediate Value Theorem to show that there is a root of the given equation in the specified interval. x4 + x - 7 = 0, (1, 2) f(x) = x² + x - 7 is ---Select--- on the closed interval [1, 2], f(1) = , and f(2)= Since -5<? < 11, there is a number c in (1, 2) such that f(c) = ? by the Intermediate Value Theorem. Thus, there is a ---Select--- ✓of the equation x² + x - 7 = 0 in the interval (1, 2).
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