Use the method of Example 9.5.10 to answer the following questions. (a) How many 15-bit strings contain exactly seven 1's? The number of 15-bit strings that contain exactly seven 1's equals the number of ways to choose the positions for the 1's in the string, namely. (b) How many 15-bit strings contain at least twelve 1's? (c) How many 15-bit strings contain at least one 1? (d) How many 15-bit strings contain at most one 1?

Q: A password contains eight digits, such as 17466780. How many different passwords be formed?

A: Here  Password contains 8 digits

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A: Here the two different four number list of Fibonacci  number with the property.

Q: A password contains eight digits, such as 17466780. How many different passwords can be formed?

A: no.of digits(0 to 9)=10

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Q: 1. How many different bit strings of length seven are there?

A:

Q: How

A: Here use combination

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Q: QUESTION 7. Consider the set of all strings of length 8 that satisfy (i) It contains three digits…

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Q: How many 12-bit strings contain exactly five 1's?   (b) How many 12-bit strings contain at least…

A: a) We can pick 5 positions for 1's from 12 positions in 12C5= 792 ways  Answer(a): 792

Q: 14a-14d

A:

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A: Given: The number is 1.12 .

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