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1. Use the Modified Euler method to approximate the solutions to each of the following initial-value problems, and compare the results to the actual values. b. C. y = te³-2y, 0≤t≤ 1, y(0) = 0, with h = 0.5; actual solution y(t) = te³e³+ e-21 y = 1+(-y)², 2≤1≤3, y(2) = 1, with h = 0.5; actual solution y(t) = 1 + y = 1+y/t, 1≤1 ≤2, y(1) = 2, with h = 0.25; actual solution y(t) = 1 Int + 2t. y = cos 2t + sin 31, 0≤ ≤ 1, y(0) 1, with h = 0.25; actual solution y(t) = sin 2t -cos 3+ kindly solve the tick part d with modified eulers method thankyou

1. Use the Modified Euler method to approximate the solutions to each of the following initial-value problems, and compare the results to the actual values. b. C. y = te³-2y, 0≤t≤ 1, y(0) = 0, with h = 0.5; actual solution y(t) = te³e³+ e-21 y = 1+(-y)², 2≤1≤3, y(2) = 1, with h = 0.5; actual solution y(t) = 1 + y = 1+y/t, 1≤1 ≤2, y(1) = 2, with h = 0.25; actual solution y(t) = 1 Int + 2t. y = cos 2t + sin 31, 0≤ ≤ 1, y(0) 1, with h = 0.25; actual solution y(t) = sin 2t -cos 3+ kindly solve the tick part d with modified eulers method thankyou

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section: Chapter Questions
Problem 5T
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1. Use the Modified Euler method to approximate the solutions to each of the following initial-value problems, and compare the results to the actual values. b. C. y = te³ - 2y, 0≤t≤1, y(0) = 0, with h = 0.5; actual solution y(t) = te³e³+ e-21 y = 1+(-y)², 2≤1≤3, y(2) = 1, with h = 0.5; actual solution y(t) = 1 + y = 1+y/t, 1≤1 ≤2, y(1)=2, with h = 0.25; actual solution y(t) = 1 Int + 2t. 0≤ t ≤ 1, y(0) 1, with h = 0.25; actual solution y(t) = y = cos 2t + sin 31, sin 21-cos 3+. kindly solve the tick part d with modified eulers method thankyou
Transcribed Image Text:1. Use the Modified Euler method to approximate the solutions to each of the following initial-value problems, and compare the results to the actual values. b. C. y = te³ - 2y, 0≤t≤1, y(0) = 0, with h = 0.5; actual solution y(t) = te³e³+ e-21 y = 1+(-y)², 2≤1≤3, y(2) = 1, with h = 0.5; actual solution y(t) = 1 + y = 1+y/t, 1≤1 ≤2, y(1)=2, with h = 0.25; actual solution y(t) = 1 Int + 2t. 0≤ t ≤ 1, y(0) 1, with h = 0.25; actual solution y(t) = y = cos 2t + sin 31, sin 21-cos 3+. kindly solve the tick part d with modified eulers method thankyou
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