Use the position equations = -16t² + vot + sowhere s represents the height of an object (in feet), vo represents the initial velocity of the object (in feet per second), s, represents the initial height of theobject (in feet), and t represents the time (in seconds).A projectile is fired straight upward from ground level (s, =- 0) with an initial velocity of 96 feet per second.calcOpera(a) At what instant will it be back at ground level?FunctisecSymbe(b) When will the height exceed 128 feet? (Enter your answer using interval notation.)RelaticSetsVi o!Vector

Given values - Initial velocity = Vi=96 ftsAngle=θ=900Acceleration due to gravity=g=32.185 fts2

Answered: Use the position equation s = -16t² +…

An Introduction to Physical Science

14th Edition

ISBN:9781305079137

Author:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres

Publisher:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres

Chapter2: Motion

Section: Chapter Questions

Problem KM

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The height of a projectile fired upward is given by the formula s=v0t-16t2, where s is the height, v0 is the initial velocity, and t is the time. Find the time for a projectile to return to Earth if it has an initial velocity of 184 ft/s
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An athlete whose event is the shot put releases the shot with the sameinitial velocity but at different angles. The figure shows the parabolic paths for shots released at angles of 35° and 65°. Solve the following based on the functions that model the parabolic paths. When the shot whose path is shown by the red graph is released at an angle of 65°, its height, g(x), in feet, can be modeled by g(x) = -0.04x2 + 2.1x + 6.1, where x is the shot’s horizontal distance, in feet, from its point of release. Use this model to solve the below parts (a) through (c) and verify your answers using the red graph. a. What is the maximum height, to the nearest tenth of a foot, of the shot and how far from its point of release does this occur? b. What is the shot’s maximum horizontal distance, to the nearest tenth of a foot, or the distance of the throw? c. From what height was the shot released?
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se the position equation s = −16t2 + v0t + s0 where s represents the height of an object (in feet), v0 represents the initial velocity of the object (in feet per second), s0 represents the initial height of the object (in feet), and t represents the time (in seconds). A projectile is fired straight upward from ground level (s0 = 0) with an initial velocity of 128 feet per second. (b) When will the height be less than 128 feet? (Only consider the time from launch to landing. Enter your answer using interval notation.)
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