Use the simplex method to solve the following. z = 4x1 + 4x2 - 8x3 10x3 s 95 12x3 s 128 X1 20, x2 2 0, X3 2 0. Maximize subject to 5x1 + 5x2 6x1 + 6x2 ..... Select the correct choice below and, if necessary, fill in the answer box to complete your choice. O A. Treating x, as a nonbasic variable, the maximum is when x1 =, X2 = , X3 = , s, = 0 and s, = O B. There is no maximum solution for this problem.
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- Solve the following LP using Simplex method Minimise Z = 60x1 + 80x2 Subject to 20x1 + 30x2 ≥ 900 Resource 1 40x1 + 30x2 ≥ 1200 Resource 2 x1, x2 ≥ 0 You are required to find Optimum product mix and minimum Optimum solution so obtained is unique or has multiple optimum solution, justify your answer. Comment on the values you have got for S1 and S2 in the optimum solution, what do they represent. Check whether both the resources are fully utilized or not. If these resources are made available for one more unit what is the effect on the cost?Solve the following LPP using Simplex method. Max P = 12X + 16Y Subject to: 10x + 20y <= 120 8x + 8y <= 80 Where X >=0 and Y >= 0Therefore, the solution from the simplex tableau is as shown below. x1 =_____ x2=_____ x3=______ S1=______ s2=______ z=______
- 2. Use the standard simplex method to solve using your first pivot choice. Provide the sequence of points given in the tableau. Maximize: P=5x+4y Subject to: 2x+y<=80 2x+3y<=120 4x+y<=160 x>=0,y>=0Solve the following problem using the simplex method: Maximize: z=2x+3y table row cell 2 x minus y less or equal than 5 end cell row cell x plus y less or equal than 6 end cell row cell x greater or equal than 0 comma space y greater or equal than 0 end cell end tableBefore selecting the correct answer to the problem, the first thing to do is formulate and solve the problem by the Simplex Method. The resolution of the problem is manual and includes: 6 steps of the procedure for the formulation of the mathematical model and the 9 steps of the Simplex Method. Don't forget to work with whole numbers or fractions. Given the problem. One company sells two different mixes of nuts. The cheapest mix contains 80% peanuts and 20% walnuts, while the most expensive contains 50% of each type. Each week the company sources 1,800 kilos of peanuts and 1,200 kilos of walnuts from its supply sources. How many kilos of each mix should he produce in order to maximize profit if the profit is $ 10 for every kilo of the cheapest mix and $ 15 for every kilo of the most expensive mix? If x1 = the Amount of mix of the CHEAP brand in kilograms, x2 = the Amount of mix of the CARA brand in kilograms. Mixture Peanut Walnut Earnings per week CHEAP 80% 20% 10$ per Kilo…
- Use the simplex method to solve the problem: Maximize: P = 3x1 + 2x2 subject to: 5x1 + 2x2 ≤ 20 3x1 + 2x2 ≤ 16 x1 ≥ 0, x2 ≥ 0Solve the problem by graphic methodMin z = 4X1 + 2X2Subject to3X1 + 5X2 ≥ 156X1 + 4X2 ≤ 24X1 ≥ 2X1 , X2 ≥ 0By investing x units of labor and y units of capital, a watch manufacturer can produce P(x, y) = 50x^0.4y^0.6 watches. Find the maximum number of watches that can be produced on a budget of $20,000 if labor costs $100 per unit and capital costs $200 per unit. That is the budget constraint given by 100x + 200y - 20,000 = 0.
- I have To use the simplex method of linear programming and answer with the ratio of row 1 and 2 and the simplex tablea: Maximize M=x+2y subject to: -x+y< (or equal to) 100 6x+6y< (or equal to) 1200 x> (or equal to) 0 y> (or equal to) 0Solve the following problem by using the Simplex approach: Maximize Z = 4X1 – 6X2 Subject to: 3X1 + 2X2 > 6 2X1 + X2 < 2 3X1 – 2X2 < 4 all variables > 0(C) Find the optimal solution of the modified problem by applying the simplex method to the initial simplex tableau. Select the correct choice below and fill in any answer boxes within your choice. X1 = ? x2=? S1 = ? a1=? P=? (D) Find the optimal solution of the original problem, if it exists. Select the correct choice below and fill in any answer boxes within your choice. Max P= ? at x1 =? X2 = ?