Use the two-path test to prove that the following limit does not exist. x+2y x- 2y What value does f(x.y) = аpproach (x,y) approaches (0,0) along the x-axis? Select the correct choice below and, if necessary, fill in the answer box to complete your choice. x+ 2y (xy)-(0.0) x- 2y lim O A. f(x.y) approaches. (Simplify your answer.) O B. f(x,y) has no limit and does not approach oo or - 00 as (x.y) approaches (0,0) along the x-axis. What value does f(x.y) = approach as (x,y) approaches (0,0) along the y-axis? Select the correct choice below and, if necessary, fill in the answer box to complete your choice. x-2y O A. f(x.y) approaches (Simplify your answer.) O B. f(x,y) has no limit and does not approach oo or - 00 as (x.y) approaches (0,0) along the y-axis. Why does the given limit not exist? O A. As (x,y) approaches (0,0) along different paths, f(x,y) always approaches the same value. . O B. As (x,y) approaches (0,0) along different paths, f(x,y) does not always approach a finite value. O C. The limit does not exist because as (x,y) approaches (0,0), the denominator approaches 0. O D. As (x.y) approaches (0,0) along different paths, f(x.y) approaches two different values.

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10. Please help me answer all parts to this calculus problem.
Use the two-path test to prove that the following limit does not exist.
x+2y
approach a
x-2y
What value does f(x.y) =
(x,y) approaches (0,0) along the x-axis? Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
x+2y
lim
(Ky)-(0.0) X- 2y
O A. f(x.y) approaches.
(Simplify your answer.)
O B. f(x.y) has no limit and does not approach oo or - 00 as (x.y) approaches (0,0) along the x-axis.
x+2y
What value does f(x,y) =
x+2y
approach as (x,y) approaches (0,0) along the y-axis? Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
O A. f(x.y) approaches
(Simplify your answer.)
O B. f(x.y) has no limit and does not approach oo or - 00 as (x.y) approaches (0,0) along the y-axis.
Why does the given limit not exist?
O A. As (x,y) approaches (0,0) along different paths, f(x,y) always approaches the same value.
O B. As (x,y) approaches (0,0) along different paths, f(x,y) does not always approach a finite value.
OC. The limit does not exist because as (x,y) approaches (0,0), the denominator approaches 0.
O D. As (x.y) approaches (0,0) along different paths, f(x.y) approaches two different values.
Transcribed Image Text:Use the two-path test to prove that the following limit does not exist. x+2y approach a x-2y What value does f(x.y) = (x,y) approaches (0,0) along the x-axis? Select the correct choice below and, if necessary, fill in the answer box to complete your choice. x+2y lim (Ky)-(0.0) X- 2y O A. f(x.y) approaches. (Simplify your answer.) O B. f(x.y) has no limit and does not approach oo or - 00 as (x.y) approaches (0,0) along the x-axis. x+2y What value does f(x,y) = x+2y approach as (x,y) approaches (0,0) along the y-axis? Select the correct choice below and, if necessary, fill in the answer box to complete your choice. O A. f(x.y) approaches (Simplify your answer.) O B. f(x.y) has no limit and does not approach oo or - 00 as (x.y) approaches (0,0) along the y-axis. Why does the given limit not exist? O A. As (x,y) approaches (0,0) along different paths, f(x,y) always approaches the same value. O B. As (x,y) approaches (0,0) along different paths, f(x,y) does not always approach a finite value. OC. The limit does not exist because as (x,y) approaches (0,0), the denominator approaches 0. O D. As (x.y) approaches (0,0) along different paths, f(x.y) approaches two different values.
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