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Using integration by partial fractions the integral / 2r²+6x – 1 x3+x2+x -dx is equivalent to Bx +C + x2+x+1 A (A) dx В C B -+ - +- X+1 X- 1 B dx + x2+x+1 A B C dx (x+1) 2 -+ x+1

Using integration by partial fractions the integral / 2r²+6x – 1 x3+x2+x -dx is equivalent to Bx +C + x2+x+1 A (A) dx В C B -+ - +- X+1 X- 1 B dx + x2+x+1 A B C dx (x+1) 2 -+ x+1

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter9: Systems Of Equations And Inequalities
Section9.10: Partial Fractions
Problem 12E
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"2x2+ бх — 1 Using integration by partial fractions, the integral x3+x²+x -dx is equivalent to Вх+ С A dx + x2+x+1 A B C dx + x+1 X- 1 B + dx x+x+1 В -+ + (x+1)2 dr x+1
Transcribed Image Text:"2x2+ бх — 1 Using integration by partial fractions, the integral x3+x²+x -dx is equivalent to Вх+ С A dx + x2+x+1 A B C dx + x+1 X- 1 B + dx x+x+1 В -+ + (x+1)2 dr x+1
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