Using switch write a program to insert two float numbers of and an arithmetic effect that refers to the calculations used(/,*,- ,+) # includeusing namespace std; int main (){float a , b; char op ; cout << " Enter Two Real Numbers : ";cin>>a>>b; cout << " Enter Operator : ";cin >>op ;switch (op) {case '+' cout <

Using switch write a program to insert two float numbers of and an arithmetic effect that refers to the calculations used(/,*,- ,+) # includeusing namespace std; int main (){float a , b; char op ; cout << " Enter Two Real Numbers : ";cin>>a>>b; cout << " Enter Operator : ";cin >>op ;switch (op) {case '+' cout <

C++ for Engineers and Scientists

4th Edition

ISBN:9781133187844

Author:Bronson, Gary J.

Publisher:Bronson, Gary J.

Chapter6: Modularity Using Functions

Section6.4: A Case Study: Rectangular To Polar Coordinate Conversion

Problem 9E: (Numerical) Write a program that tests the effectiveness of the rand() library function. Start by...

See similar textbooks

Similar questions

Implement in C Programming 6.10.2: Pass by pointer. Write a function call to ConvertMoney() to store the number of quarters, nickels, and pennies within the integer variables numQuarters, numNickels, and numPennies, respectively. Ex: If the input is 133, then the output is: Quarters: 5 Nickels: 1 Pennies: 3 #include <stdio.h> void ConvertMoney(int totalPennies, int* numQuarters, int* numNickels, int* numPennies) { *numQuarters = totalPennies / 25; totalPennies = totalPennies % 25; *numNickels = totalPennies / 5; totalPennies = totalPennies % 5; *numPennies = totalPennies;} int main(void) { int totalPennies; int numQuarters; int numNickels; int numPennies; scanf("%d", &totalPennies); /* Your code goes here */ printf("Quarters: %d\n", numQuarters); printf("Nickels: %d\n", numNickels); printf("Pennies: %d\n", numPennies); return 0;}
In C++ write a program that generates three random numbers and then find the min number among the generated values, using these three functions: void getrandnum(int &n1, int &n2, int &n3), int findMin(int n1, int n2, int n3), and void printResult(int n1, int n2, int n3, int min). Make the main function drive all these functions.
1.The following is the C code that you need to implement for this lab: uint8_ t f(uint8_tn) return(n<2)?(n):(f(n-1)+f(n-2)); The main function can be assumed as follows: int main() uint8_ t x; x=f(???); return 0; Obviously, " ? ? ? " is representing a value used to test the algorithm! Is "f"recursive? a.No answer text provided. b.Yes c.no d.depends on whether it is in for main 2.First, make the code in the previous question an actual C program so that it can be compiled and it runs. Play with it so that you feel comfortable with the logic of the code. Then implement the code in TTPASM. Note that you need to preserve the actual C code structure, this means you cannot it into a non-recursive subroutine. Furthermoreall conventions discussed in class regarding subroutines must be followed. The idea is that I should be able to substitute f with my own code, and main should work. Or, I can substitute main with my own, and f should work. Attach the source code of your assembly…
In C++: Examine the code segment. What will be printed? If there are any errors indicate the nature of each error. int a[7] = {31, 12, 32, 14, 25, 16, 27}; int *ptr; ptr = & a[2]; for ( i=1; i<=5; i=i+2) cout << *(ptr +i); cout << a[0] << *ptr << *ptr - 2 << *(ptr -1)) << endl;
The program will ask the user for their name and employee ID. The ID will be a five-digit number. This will be done in a single function, AskNameId, with bool return, where the name and id are passed as pointers. Read both variables as strings with a getline and convert the id to an int using atoi. Check that the id is not 0. If it is, cout a message to the user for entering an invalid id. Check if the name is an empty string. If it is, cout a message to the user for entering an invalid name. Return a bool, true if name and id are both valid and false if either one is not valid.
The program below stores 80 bool values into a char arr[10]. CompletesetBool and getBool. In both functions, index is the index of the boolvalues, from 0 to 79. getBool returns 1 if the bool value at index is trueotherwise 0. You will probably need most bitwise operations including shifting. void setBool ( char * arr , int index , int boolValue ) {}int getBool ( char * arr , int index ) {}int main ( void ) {char arr [10];memset ( arr , 0 , 10);setBool ( arr , 78 , 1);setBool ( arr , 40 , 0);int b78 = getBool ( arr , 78); // b78 is 1int b40 = getBool ( arr , 40); // b40 is 0return 0;}
Write java overloaded function calculate() with following function definitions.void calculate(int x, int y ) – to calculate the sum of all even numbers from xtill y and print the sum .void calculate(char a,char n) – to print all vowels from variable a to n if anyvoid calculate(int x, int y, int z) – to print the middle number from x,y,z ifyou arrange them in ascending order.
I wrote this c++ program to find min and max, but why does the program say it cannot find the min and max. WHere I got wrong? Please help me revise my code. I have must use the pointer and void function in my code. Please help me revise it. #include <iostream>using namespace std; int getmin(int number[], int size){ int min=number[0]; for (int i=1; i<size; i++) { if (number[i]<min) min=number[i]; } return min;}int getmax(int number[], int size){ int max=number[0]; for (int i=1; i<size; i++) { if (number[i]>max) max=number[i]; } return max;}void getminandmax(int number[], int size, int* min, int* max) { for (int i=1; i<size; i++) { if (number[i] > *max) *max=number[i]; if (number[i] < *min) *min=number[i]; } } int main(){ int number[5]={5, 4, -2, 29, 6}; int min=number[0]; int max=number[0]; getminandmax(number, 5, &min, &max);…
Correct this code written in c. hint: the last ending (// calling function) #include<stdio.h>#include<math.h> function(float x, float y, int n){int i;float R,R_power_n=1,realpart,impart,theta;R=sqrt((x*x)+(y*y));theta = tan(y/x); // since tan inverse theta = y/x i.e., theta = tan(y/x) for(i=1;i<=n;i++) // loop for calculation of R power n value{R_power_n = R_power_n*R;} // R power n result stored in R_power_ntheta=n*theta; //calculating n thetarealpart=R_power_n*cos(theta); // Calculating real partimpart=R_power_n*sin(theta); // Calculating imaginary partprintf("\n%.2f + j%.2f", x,y);printf("\n\nPower of %d is %.2f + j%.2f\n\n", n,realpart,impart);}int main(){int main(){int n;float x;float y; // Because of real numbers, take x and y as float data typeprintf("\nEnter real values x:");scanf("%f",&x);printf("\nEnter real values y:");scanf("%f",&y);printf("\nEnter the n Value:");scanf("%d",&n);(x,y)=fuction(x,y,n); // calling function}
I). Write a program in c++ with class that will help an elementary school student learn multiplication. Use the rand function to produce two positive one-digit integers. The program should then prompt the user with a question, such as How much is 6 times 7? The student then inputs the answer. Next, the program checks the student’s answer. If it’s correct, display the message "Very good!" and ask another multiplication question. If the answer is wrong, display the message "No. Please try again." and let the student try the same question repeatedly until the student finally gets it right. A separate function should be used to generate each new question. This function should be called once when the application begins execution and each time the user answers the question correctly.
When a variable is stored in memory, it is associated with an address. To obtain the address of avariable, the & operator can be used. For example, &a gets the memory address of variable a.Let's try some examples.Write a C program addressOfScalar.c by inserting the code below in the main function. 1 // intialize a char variable, print its address and the next address2 char charvar = 'a';3 printf("address of charvar = %p\n", (void *)(&charvar));4 printf("address of charvar - 1 = %p\n", (void *)(&charvar - 1));5 printf("address of charvar + 1 = %p\n", (void *)(&charvar + 1));67 // intialize an int variable, print its address and the next address8 double doublevar = 1.0;9 printf("address of doublevar = %p\n", (void *)(&doublevar));10 printf("address of doublevar - 1 = %p\n", (void *)(&doublevar - 1));11 printf("address of doublevar + 1 = %p\n", (void *)(&doublevar + 1)); Questions:1) Run the C program, attach a screenshot of the output in the answer…
Write output of the following c++ code by completing it with explanation of all iterations Need explanation of code line by line how it will execute. Code #include <iostream> Using namespace std; int fun1(int); int fun(float); int fun1(int n){ if(n<=1) return 1; else return n*fun(n-1); } int fun(float n){ if(n<=1) return 1; else return n*fun(n-1); } int main(){ int n=5; cout<<fun1(n); cout<<fun(4.3); return 0; }