When a variable is stored in memory, it is associated with an address. To obtain the address of a variable, the & operator can be used. For example, &a gets the memory address of variable a. Let's try some examples. Write a C program addressOfScalar.c by inserting the code below in the main function.   1 // intialize a char variable, print its address and the next address 2 char charvar = 'a'; 3 printf("address of charvar = %p\n", (void *)(&charvar)); 4 printf("address of charvar - 1 = %p\n", (void *)(&charvar - 1)); 5 printf("address of charvar + 1 = %p\n", (void *)(&charvar + 1)); 6 7 // intialize an int variable, print its address and the next address 8 double doublevar = 1.0; 9 printf("address of doublevar = %p\n", (void *)(&doublevar)); 10 printf("address of doublevar - 1 = %p\n", (void *)(&doublevar - 1)); 11 printf("address of doublevar + 1 = %p\n", (void *)(&doublevar + 1)); Questions: 1) Run the C program, attach a screenshot of the output in the answer sheet. 2) Attach the source code in the answer sheet 3) Then explain why the address after doublevar is incremented by 8 bytes instead of 1 byte.

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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When a variable is stored in memory, it is associated with an address. To obtain the address of a
variable, the & operator can be used. For example, &a gets the memory address of variable a.
Let's try some examples.
Write a C program addressOfScalar.c by inserting the code below in the main function.

 

1 // intialize a char variable, print its address and the next address
2 char charvar = 'a';
3 printf("address of charvar = %p\n", (void *)(&charvar));
4 printf("address of charvar - 1 = %p\n", (void *)(&charvar - 1));
5 printf("address of charvar + 1 = %p\n", (void *)(&charvar + 1));
6
7 // intialize an int variable, print its address and the next address
8 double doublevar = 1.0;
9 printf("address of doublevar = %p\n", (void *)(&doublevar));
10 printf("address of doublevar - 1 = %p\n", (void *)(&doublevar - 1));
11 printf("address of doublevar + 1 = %p\n", (void *)(&doublevar + 1));

Questions:
1) Run the C program, attach a screenshot of the output in the answer sheet.
2) Attach the source code in the answer sheet
3) Then explain why the address after doublevar is incremented by 8 bytes instead of 1 byte. 

 

 

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