Using the below figure 1. The private enterprise's subtree below gives the object ID for these Objects: Cisco, hp, 3com, and Cabletron.
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- Q2: No HandWriting, Using the below figure 1. The private enterprise’s subtree below gives the object ID for these Objects: Cisco, hp, 3com, and Cabletron.Let relations r1(A, B, C) and r2(C, D, E) have the following properties: r1 has20,000 tuples, r2 has 45,000 tuples, 25 tuples of r1 fit on one block, and 30tuples of r2 fit on one block. Estimate the number of block transfers and seeksrequired using each of the following join strategies for r1 ⋈ r2: Merge join.Let relations r1(A, B, C) and r2(C, D, E) have the following properties: r1 has20,000 tuples, r2 has 45,000 tuples, 25 tuples of r1 fit on one block, and 30tuples of r2 fit on one block. Estimate the number of block transfers and seeksrequired using each of the following join strategies for r1 ⋈ r2: Block nested-loop join.
- Let relations r1(A, B, C) and r2(C, D, E) have the following properties: r1 has20,000 tuples, r2 has 45,000 tuples, 25 tuples of r1 fit on one block, and 30tuples of r2 fit on one block. Estimate the number of block transfers and seeksrequired using each of the following join strategies for r1 ⋈ r2: Nested-loop join.Exercise 12.4 Consider the following schema with the Sailors relation: Sailors(sid: integer, sname: string, rating: integer, age: real) For each of the following indexes, list whether the index matches the given selection conditions. If there is a match, list the primary conjuncts. A B+-tree index on the search key < Sailors.sid >. σSailors.sid<50,000(Sailors) σSailors.sid=50,000(Sailors) A hash index on the search key < Sailors.sid >. σSailors.sid<50,000(Sailors) σSailors.sid=50,000(Sailors) A B+-tree index on the search key < Sailors.sid, Sailors.age >. σSailors.sid<50,000∧Sailors.age=21(Sailors) σSailors.sid=50,000∧Sailors.age>21(Sailors) σSailors.sid=50,000(Sailors) σSailors.age=21(Sailors) A hash index on the search key < Sailors.sid, Sailors.age >. σSailors.sid=50,000∧Sailors.age=21(Sailors) σSailors.sid=50,000∧Sailors.age>21(Sailors) σSailors.sid=50,000(Sailors) σSailors.age=21(Sailors) (note that the book has a typo for part 4,…3. Assume that relation PROJ of our example database above is horizontally fragmented as follows: PROJO PNOS P2 (PROJ) PROJ₂ = PNO P2 (PROJ) And, the relation ASG is horizontally fragmented as ASGO PNOS P2 (ASG) ASG₂ = σ "P2" <PNOS P3 (ASG) ASG=σPNO>P3 (ASG) 1) Transform the following query into a reduced query on fragments: and 2) Is it better than the generic query? And Why? or Why not? SELECT RESP, BUDGET FROM ASG, PROJ WHERE ASG.PNO PROJ.PNO AND PNAME="CAD/CAM" =
- You have hypothetically obtained access to a database listing the locations (in x, y coordinates) and names of all nearby restaurants. Only the following kind of questions are required: The question seeks to determine whether the given location is suitable for an eating establishment. I was wondering if you could explain why R-tree indexing was better than B-tree. Why?Imagine having access to a database containing the x, y coordinates and names of numerous restaurants. Let's assume that only the following types of inquiries are being made: The focus of the investigation is whether or not a restaurant can be located at a particular location. Which indexing technique is superior: It is either a B-tree or an R-tree. Why?Given:1. The universal relation schema Q(CTHRSG), where C = course, T = teacher, H = hour, R = room, S= student, and G = grade.2. The minimal set of functional dependencies F are assumed: C ->T each course has one teacher HR -> C only one course can meet in a room at one time. HT -> R a teacher can be in only one room at one time. CS -> G each student has one grade in each course. HS -> R a student can be in only one room at one time. 3. The decomposition of the universal schema Q(CTHRSG) based on the algorithm (Lossless Join and Dependency-Preserving Decomposition into 3NF Relation Schema) is:D = {R1, R2, R3, R4, R5}, where R1 = {CT} R2 = {HRC} R3 = {HTR} R4 = {CSG} R5 = {HSR} 4. HS is the key of R, and is a part of R5. Please apply the Lossless Join Testing algorithm to see if the decomposition D is a lossless join decomposition. Please provide testing details step by step when you apply the set of functional dependency for testing.
- Consider a relation schema R = {M, N, P, Q, S} and its functional dependency set F = {N → Q,S → M,M →P,P → S}. Is MN a super key of R? Is MN a candidate key of R? (a) MN is not a super key for R; MN is not a candidate key for R.(b) MN is a super key for R; MN is not a candidate key for R.(c) MN is a super key for R; MN is a candidate key for R.(d) MN is not a super key for R; MN is a candidate key for R.1. What technique is used to model the situation that Student may have multiple addresses? A) Associative Entity (gerund)B) Weak entitiesC) Super/sub typesD) Recursive relationships 2.There is m:m relationship between students and classes. Which technique is used forrepresenting the student grade? A) Associative Entity (gerund)B) Weak entitiesC) Super/sub typesD) Recursive relationships 3. An associative Entity (gerund) may be used whenever there are data that depends on twoentities even when their relationship is 1:m. True or FalseA) TrueB) False 4. (check all that apply) When do you use recursive relationships?A) the relationship between employees and their supervisorsB) the relationship between employees and their dependentsC) the relationship between employees and their departmentsD) the relationship between employees and their team membersE) the relationship between employees and their job assignments 5. How is a gerund converted into a relational model?A) ignore the gerund in the…Given the following relation R and its functional dependencies: R(workerNumber, repairNumber, workerName, machineNumber, spentTime, repairDate, machineName, workshopNumber, workshopName ) workerNumber à workerName repairNumber à repairDate, machineNumber machineNumber à machineName, workshopNumber workshopNumber à workshopName 1)Create a database whose tables are at least in 3NF, showing the dependency diagrams for each table