Using the following data 20 = 0.3 0.43 x2 = 0.56 23 = 0.69 24 = 0.82 25 0.95 f(x) 2.3185 2.4159 2.478 2.5 2.48 2.4197 1. Af(xo) = 2. Δ f (0)= 3. A° f(zo) =

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 91E
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Using the following data
x0 = 0.3
x1 = 0.43
x2 = 0.56
æ3 = 0.69
24 = 0.82
25 = 0.95
f(x)
2.3185
2.4159
2.478
2.5
2.48
2.4197
1. Af(æ0) =
2. A²f(xo) =
3. A³ f(zo) =
4. A³f(æ2) =
5. Aʻf(x0) =
6. Aʻf(æ1) =
7. Δf (0)
8. To approximate f(0.60333333333333) what value of s should be used in newton's forward
difference formula? s =
(:)
(:)
9.
10.
11. Using Newton's forward difference formula, what is the approximation for f(0.60333333333333)
Transcribed Image Text:Using the following data x0 = 0.3 x1 = 0.43 x2 = 0.56 æ3 = 0.69 24 = 0.82 25 = 0.95 f(x) 2.3185 2.4159 2.478 2.5 2.48 2.4197 1. Af(æ0) = 2. A²f(xo) = 3. A³ f(zo) = 4. A³f(æ2) = 5. Aʻf(x0) = 6. Aʻf(æ1) = 7. Δf (0) 8. To approximate f(0.60333333333333) what value of s should be used in newton's forward difference formula? s = (:) (:) 9. 10. 11. Using Newton's forward difference formula, what is the approximation for f(0.60333333333333)
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