Using the intermediate value theorem, determine, if possible, whether the function f has at least one real zero between a and b. f(x) = x² + 5x² - 8x-37; a= -9, b = - 3 Select the correct choice below and, if necessary, fill in the answer boxes to complete your choice. OA. By the intermediate value theorem, the function has at least one real zero between a and b because f(a) = OB. By the intermediate value theorem, the function does not have at least one real zero between a and b because f(a) = and f(b) = OC. It is impossible to use the intermediate value theorem in this case. and f(b) = (Simplify your ar (Simpl
Using the intermediate value theorem, determine, if possible, whether the function f has at least one real zero between a and b. f(x) = x² + 5x² - 8x-37; a= -9, b = - 3 Select the correct choice below and, if necessary, fill in the answer boxes to complete your choice. OA. By the intermediate value theorem, the function has at least one real zero between a and b because f(a) = OB. By the intermediate value theorem, the function does not have at least one real zero between a and b because f(a) = and f(b) = OC. It is impossible to use the intermediate value theorem in this case. and f(b) = (Simplify your ar (Simpl
Chapter3: Polynomial Functions
Section: Chapter Questions
Problem 4T: The path of a ball is modeled by the function f(x)=120x2+3x+5, where fx is the height (in feet) of...
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Transcribed Image Text:Using the intermediate value theorem, determine, if possible, whether the function f has at least one real zero between a and b.
3
f(x) = x³ + 5x².
+5x8x-37; a = -9, b = -3
...
Select the correct choice below and, if necessary, fill in the answer boxes to complete your choice.
OA. By the intermediate value theorem, the function has at least one real zero between a and b because f(a)= and f(b) =
OB. By the intermediate value theorem, the function does not have at least one real zero between a and b because f(a) =
OC. It is impossible to use the intermediate value theorem in this case.
(Simplify your ar
(Simpl
and f(b) =
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