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- Using the techniques discussed in this section, solve the following system of linear equations. Enter the solution as an ordered pair. For parametric solutions use either x = tor y = t as the param- (If an answer does not exist, enter DNE.) (x, y) = -14x + 18y = 16 7x - 9y = -8 XUsing the techniques discussed in this section, solve the following system of linear equations. Enter the solution as an ordered triple. For parametric solutions use z = t as the parameter. (If an answer does not exist, enter DNE.) 4x − 2y − 4z = −6 2x + 3y − 9z = −21 x − y − 6z = −11 (x, y, z) =Solve the following system of equations. (Enter your answers as a comma-separated list. If there are infinitely many solutions, enter a parametric solution using t and/or s. If there is no solution, enter NONE.) 2x - 16y - 6z= 33 -4x + 32y +12z = -44 (x, y, z) =
- Solve the following system of equations. (Enter your answers as a comma-separated list. If there are infinitely many solutions, enter a parametric solution using t and/or s. If there is no solution, enter NONE.) 2x − 18y − 8z = 33 -4x + 36y + 16z = -44 (x, y, z)=Solve the following system of equations. (Enter your answers as a comma-separated list. If there are infinitely many solutions, enter a parametric solution using t and/or s. If there is no solution, enter NONE.) 3y + 2z = 1 2x − y − 3z = 4 2x + 2y − z = 5 (x, y, z)=Solve the following system of equations. (Enter your answers as a comma-separated list. If there are infinitely many solutions, enter a parametric solution using t and/or s. If there is no solution, enter NONE.) x1 + 2x2 + 6x3 = 6 x1 + x2 + 3x3 = 3 (x1, x2, x3) =
- Solve the following system of equations. (Enter your answers as a comma-separated list. If there are infinitely many solutions, enter a parametric solution using t and/or s. If there is no solution, enter NONE.) 3x − 2y + z = 2 x + 3y − 4z = 5 2x − 3y + 5z = −3 x − 8y + 9z = −8 (x, y, z)=4x^2+16y^2-16x+192y+528=0 I solved and got (x-2)^2+(y+6)^2/4 =1 the center is (2,-6) I need help finding the foci and verticesThe System of conics has two solutions (x-1)^2+(y+4)^2=25 (x-1)^2/25 + (y+4)^2/100 =1 What are the solutions to the conic?
- The general second degree equation has the form Ax2 + Bxy + Cy2 + Dx + Ey + F = 0. If B2 – 4AC = 0 describes an ellipse if a. B2 – 4AC = 0 b. B2 – 4AC = 1 b. B2 – 4AC > 0 d. B2 – 4AC < 0Linear algebra :Conic Write the equations of the following paraballsA) Focus F(0.2) and guideline y=-2B) Focus F(0.2) and guideline y=-4Find an equation of a sphere with radius r and center C(h, k, l). SOLUTION By definition, a sphere is the set of all points P(x, y, z) whose distance from C is r. (See the figure.) Thus, in terms of r, P is on the sphere if and only if |PC| = . Squaring both sides, in terms of radius r, we have |PC|2 = . In terms of Cartesian coordinates and radius r, the equation of a sphere is (x − )^2+ (y − k)^2+ (z − )^2 =