Using trigonometric substitution, what is 2 A sec-1 (3) - x²-g 6x² ® 1/1 sec - ¹ (1/3) - B x²-9 2x² + C Ⓒ / Dec ²¹ ( 3 ) + √x ² = 0 + 0 C C 2x² © ²000-¹1( 5 ) + √²²-9 + D sec C 6x² √√x²=91 +3 + C dx?

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