?VmIn the above image we see a 3.43 kg box that is moving to the right at 19.5 m/s. The box hits into a rough patch that applies a frictional force of 277 Newtons until the box comes to a stop.time K.E.E.P.E.JoulesG.P.E.M.EInitialJoulesJoulesJoulesFinalJoulesJoulesJoulesJoulesHow much work was done on the box by friction?JoulesHow far would the box travel before coming to a stop?meters

Answered: Image /qna-images/answer/e4411f9a-cdad-4777-8267-c5dfd4922bbf.jpg

? V In the above image we see a 3.43 kg box that is moving to the right at 19.5 m/s. The box hits into a rough patch that applies a frictional force of 277 Newtons until the box comes to a stop. time K.E. G.P.E. E.P.E. M.E |Joules |Joules Joules Joules |Joules | Joules Initial Joules Final Joules How much work was done on the box by friction? Joules How far would the box travel before coming to a stop? meters

? V In the above image we see a 3.43 kg box that is moving to the right at 19.5 m/s. The box hits into a rough patch that applies a frictional force of 277 Newtons until the box comes to a stop. time K.E. G.P.E. E.P.E. M.E |Joules |Joules Joules Joules |Joules | Joules Initial Joules Final Joules How much work was done on the box by friction? Joules How far would the box travel before coming to a stop? meters

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter11: Energy And Its Conservation

Section: Chapter Questions

Problem 55A

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Review. You can think of the workkinetic energy theorem as a second theory of motion, parallel to Newtons laws in describing how outside influences affect the motion of an object. In this problem, solve parts (a), (b), and (c) separately from parts (d) and (e) so you can compare the predictions of the two theories. A 15.0-g bullet is accelerated from rest to a speed of 780 m/s in a rifle barrel of length 72.0 cm. (a) Find the kinetic energy of the bullet as it leaves the barrel. (b) Use the workkinetic energy theorem to find the net work that is done on the bullet. (c) Use your result to part (b) to find the magnitude of the average net force that acted on the bullet while it was in the barrel. (d) Now model the bullet as a particle under constant acceleration. Find the constant acceleration of a bullet that starts from rest and gains a speed of 780 m/s over a distance of 72.0 cm. (e) Modeling the bullet as a particle under a net force, find the net force that acted on it during its acceleration. (f) What conclusion can you draw from comparing your results of parts (c) and (e)?
A 3.00-kg object has a velocity (6.00i1.00j)m/s. (a) What is its kinetic energy at this moment? (b) What is the net work done on the object if its velocity changes to (8.00i+4.00j)m/s. (Note: From the definition of the dot product, v2=vv.)
. A bicycle and rider going 10 m/s approach a hill. Their total mass is 80 kg. (a) What is their kinetic energy? (b) If the rider coasts up the hill without pedaling, how high above its starting level will the bicycle be when it finally rolls to a stop?
A 60.0-kg athlete leaps straight up into the air from a trampoline with an initial speed of 9.0 m/s. The goal of this problem is to find the maximum height she attains and her speed at half maximum height. (a) What are the interacting objects and how do they interact? (b) Select the height at which the athletes speed is 9.0 m/s as y = 0. What is her kinetic energy at this point? What is the gravitational potential energy associated with the athlete? (c) What is her kinetic energy at maximum height? What is the gravitational potential energy associated with the athlete? (d) Write a general equation for energy conservation in this case and solve for the maximum height. Substitute and obtain a numerical answer. (e) Write the general equation for energy conservation and solve for the velocity at half the maximum height. Substitute and obtain a numerical answer.
Two people observe a leaf falling from a tree. One person is standing on a ladder and the other is on the ground. If each person were to compare the energy of the leaf observed, would each person find the following to be the same or different for the leaf, from the point where it falls off the tree to when it hits the ground: (a) the kinetic energy of the leaf; (b) the change in gravitational potential energy; (c) the final gravitational potential energy?
What does work on a shuffleboard puck as it slides to rest? Why is the board dusted, and how does this affect work?
Two children stand on a platform at the top of a curving slide next to a backyard swimming pool. At the same moment the smaller child hops off to jump straight down into the pool, the bigger child releases herself at the top of the frictionless slide. (i) Upon reaching the water, the kinetic energy of the smaller child com-pared with that of the larger child is (a) greater (b) less (c) equal. (ii) Upon reaching the water, the speed of the smaller child compared with that of the larger child is (a) greater (b) less (c) equal. (iii) During their motions from the platform to the water, the average acceleration of the smaller child compared with that of the larger child is (a) greater (b) less (c) equal.
A 20-kg child is coasting at 3.3 m/s over flat ground in a 4.0-kg wagon. The child drops a 1.0-kg ball out the back of the wagon. What is the final speed of the child and wagon?
The "shot" used in the shot-put event is a metal ball with a mass of 7.3 kg. When thrown in Olympic competition, it is accelerated to a speed of about 14 m/s. As an approximation, let's say that the athlete exerts a constant force on the shot while throwing it and that it moves a distance of 3 m while accelerating. (a) What is the shot's kinetic energy? (b) Compute the force that acts on the shot. (c) It takes about 0.5 s to accelerate the shot. Compute the power required. Convert your answer to horsepower.
A 100-g toy car is propelled by a compressed spring that starts it moving. The car follows the curved track in Figure 7.39. Show that the final speed of the toy car is 0.687 m/s if its initial speed is 2.00 m/s and it coasts up the frictionless slope, gaining 0.180 m in altitude. Figure 7.39 A toy car moves up a sloped track. (credit: Leszek Leszczynski, Flickr)