В. A bubble of air is rising from the sea floor, from a depth of about 500 m. At this depth the pressure is 5.1*10° Pa (about 50.3 atm) and is at a temperature of about 7.0° C. It rises to the surface with the atmosphere, at a temperature of 20° C. If the bubble is observed to have a volume of 4 cm³ at the surface, what was its volume at the sea floor? Assume the number of moles of gas in the bubble is constant.

Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter19: Temperature, Thermal Expansion And Gas Laws
Section: Chapter Questions
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A bubble of air is rising from the sea floor, from a depth of about 500 m. At this
depth the pressure is 5.1*106 Pa (about 50.3 atm) and is at a temperature of about 7.0° C.
It rises to the surface with the atmosphere, at a temperature of 20° C. If the bubble is
observed to have a volume of 4 cm³ at the surface, what was its volume at the sea floor?
Assume the number of moles of gas in the bubble is constant.
B.
Transcribed Image Text:A bubble of air is rising from the sea floor, from a depth of about 500 m. At this depth the pressure is 5.1*106 Pa (about 50.3 atm) and is at a temperature of about 7.0° C. It rises to the surface with the atmosphere, at a temperature of 20° C. If the bubble is observed to have a volume of 4 cm³ at the surface, what was its volume at the sea floor? Assume the number of moles of gas in the bubble is constant. B.
Expert Solution
Step 1

The given values are,

P1=5.1×106 Pa=50.3 atmT1=7.0° C=7.0+273 K=280 KP2=Patm=1 atmT2=20° C=20+273 K=293 KV2=4 cm3V1=?

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