V2r – y - 2 lim (т, у) — (2,0) 2х- у — 4 2х - у4 y - 4

Q: What is the maximum vertical distance between the line y = x + 30 and the parabola y = x2 for -5 s x…

A: given, equation of line is y = x + 30 and equation of parabola is  we have to find maximum vertical…

Q: Find the abscissa of the point on the graph of y=V 2x – 1 that is parallel to the line 2x - y+1=0

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Q: b. Enclosed by the curves y² = 4x + 4 and the line y = 4x – 16.

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Q: 5) (x- 4)² + y² = 9 Center Radius

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Q: Find the point(s) on x=3-y² that are closest the point A=(1,0)

A: Our Aim is to find the points on x=3-y2 that are closest the point A=(1,0).

Q: y2 – 9 lim V 2y2 + 7y + 3

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Q: Find the linearization of-ƒ(x, y) = x2 - xy + 1- 2 y2 + 3?

A: Here we have,  f(x,y) = x2-xy+1-12y2+3 at (3,2)

Q: Solve and find limt→∞ y(t) of y′′ + 5y′ + 7y= 0

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Q: Use chain Rule to find for 2. y = . +x²+x+1 I.W | 3. y = estn 3x Н.W

A: We have to find dydx using chain rule for the given function: 2.  y=1x3+x2+x+13.  y=esin 3x We know…

Q: у-V25- х2 у%30, х%3D2, х%3D4: abour the х-аxis. *3у-у, х-0 : about the y-axis.

A: In this we use integration and simple mathematics . and , a graph which shows the above equation as…

Q: 7y lim 2 y>+∞ +3y+Vy-4y

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Q: (i) limx-0,y-0,2–0 81yz (22+7y2+6z2) answer/antwoord = %3D 9æy? 49x2+49y? (ii) limx-0,y-0…

A: Here we will calculate the limit for an individual variables. For a limit of x (Substitute y=0, z=0)…

Q: Sketch Z= 2x^2 + 3y^3

A: Given, Z=2x2+3y3 To find: Sketch the plot for Z

Q: /2x – y – 2 (b) lim (2r – y + 4) (1,y)-(2,2) 2x – y – 4

A: We can directly put the value of (x,y) if denominator is not becoming 0. Or else, we can choose a…

Q: 2ry + 6x lim (z,v)(0,–3) r² + y² + 6y +9°

A: We have to use polar coordinates here.

Q: Find ƒyxyz if ƒ(x, y, z) = 1 - 2xy2z + x2y.

A: Given that, fx, y, z=1-2xy2z+x2y           ...(1)

Q: on of y" – 2y' + 2y =

A:

Q: Find fxy when f(x, y) = 8xeXy.

A: To find fxy when fx, y=8xexy.

Q: Let y(t) be the solution of the IVP y = 2y- 3, y(1) = 2 then lim y(t) = Select one:

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Q: Find y' for x 3 + y-3 9. at the point (2, 1). | At (2, 1), y' Preview ||

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Q: y — у — 2 3. lim f(y), where f (y) = y→2 y2+ у — 6

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Q: Differentiate. ' a) y = 2cos(x²)

A: Hi, at a time we can answer only one question and the exact one was not specified. So, I have…

Q: lim a. y 2 - y 7 + 6y 4 V 5x² - 2 lim b. V 5 (x + 3)

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Q: y +7y2 +16y+ 12 lim y-2 y3 +5y? + 8y +4

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Q: (b) lim y - 2 y→2 5 – V27 - y

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Q: Find yll of x³+y²=3 by implicit ditferetlal C1o pants

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Q: y = sec* ( Vsin(2t)) sec³ 3.

A: The objective is to find the derivative.

Q: If x2 + y2 = 4 which has domain Dr=[-2,2] range Rf=[0,2]. Shrink and stretch it vertically by 3…

A: We are given:  x2+y2=4⇒y=4-x2=f(x) For shrinking vertically by 3 units , we have: f(x)→13f(x) Hence,…

Q: ? lim (z,y) (1,1) 2x – ry – y r2 – y2

A:

Q: Find dydx for…

A: the given equation of the curve is: y3+y2-5y-x2+4=0 we have to find the value of dydx

Q: dy of y3Dx dr Find csc2r,

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Q: 3)으 rcose de Jsine 1-x2 d ¿= xp 2

A: LEIBNIZ RULE

Q: Parameterize the following curve 9x 9x^2 + 4y^2 = 32y -54x-109

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Q: 3/2 y 3. dydx 3 X

A: A detailed solution is given below

Q: 2x2 + 2y? lim (x,y)→(0;0) V² + y² – 1 + 1 .2 -

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Q: 11. Perpendicular to 5y = 2x – 6 and passes through the point (-1, 5)

A: topic - equation of a line perpendicular to given line

Q: f'(x) 2 -4 -3 -2 1 2 3 4 -1 -2 -3 Concave down: 1

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Q: I Y=t5メPYove th y-2(21くるど

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Q: (18) y "+9y '= sec² 2x %3D (19) y "'+6y "–14y'–104y = -11 le*

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Q: Q1: - find dylax for y = 5cscx³

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Q: lim (2,y)→(1,1) 2a2 – ry – y? 2² – y?

A: Evaluate the limit

Q: ų (H)= - 2y, (t) + 24;(4)= Y,(4) - 2y, (t) +2t t 9,lFS +2

A:

Q: Find y' for 4x + 5y* – 1 = 132 at the point (2, – 1). | At (2, – 1), y' = Preview %3D

A: Given: 4x5+5y4-132 To find: y'  at  (2,-1)

Q: 2 lim y→7L_– 4y – 21 3y Зу — 17у — 28 -

A:

Q: Sketch Z= 2x^2+3y^2

A: To sketch: Z=2x2+3y2.

Q: A 3 X Y- X Y = 4xソーメニ2findr 3D2 and X"at X =1

A: Using definition of differentiation

Q: . lim 4y9 + V y--00 /y18 – 1

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Q: Find 1- y dy y+2 using the substitutionu +5= √√y+2.

A:

Limits

When it comes to calculus, limits are considered to be a very important topic of discussion. The main importance of limit lies in expressing the value of a function as it gets closer to a certain value. Also, limits can help you to understand other topics, such as continuity and differentiability better. In a broader sense, every calculus notion is a limit. Other branches of calculus have also been derived from limits.