V4-x 5. lim X-2- x-2

Q: Q5/B: Evaluate lim (). x→1/2 \4-x²

A: Recall: limx→a f(x) exists and equal to L if and only if limx→a- f(x) =limx→a+f(x) exists and both…

Q: Vx+5-3 b) lim x→4 х-4

A:

Q: x²-x-6 - lim x→-2 x+2

A: Since you have asked multiple questions in a single request we would be answering only the first…

Q: -4 lim x2 2-x-2

A: option (d) is correct

Q: Find the limits by rewriting the fractions first.

A:

Q: 2x + lim X→-2 X + 2 X + 2

A:

Q: 2-JA+3 「メャ 2) Lm x2x-3 3) Lim (X+4)-16

A: →When limit is of the form 00 or ∞∞ , then L' Hospital rule is used. In L'Hospital rule,     take…

Q: 4x5+x³ -10 -? lim х-0о —7х5+x2+20 .3

A: Given: limx→∞4x5+x3-10-7x5+x2+20

Q: Va² –3 –2 \, x2+1 lim x→-1

A: Given: limx→-1x2-3-2x2+1

Q: Find the limits.

A: limx→7 3xx+2

Q: x² – 21x + 54 - lim x → 3 х — 3 - II

A: x2-21x+54=x2-18x-3x+54=x(x-18)-3(x-18)=(x-18)(x-3)

Q: x²+2x-15 lim X-5 |x+5|

A:

Q: Find the limit.

A: Explanation: Given that,  limx→4x-3-1x-4

Q: V4 + x – 2 lim x→0

A: To evaluate the given limit

Q: 2. Find lim (√x + 2 = √2).

A:

Q: (а) 5x-3 – 4 (i) Lim X0 2x-2 +9 (х - 3)2 (ii) Lim- X0 X2 7- 2x – 3

A: We must know that 1∞=0 And here the  limits are (i)  -49     and (ii) 2

Q: Vx+11-4 (b) lim- x- 5 X-5

A:

Q: x2 +2x-3 lim x -3 5x +15

A: A function is said to have limit L at 'a' if all value of f(x)  approaches the real number L as the…

Q: V13-x - 2 4-Vx +7 Evaluate lim-

A:

Q: x2 -x-2 lim 12 x- 2x X-2

A:

Q: V3x2+6 Evaluate lim x--0 5-2x

A: Hey, since there are multiple questions posted, we will answer first question. If you want any…

Q: (a) 5x-3 – 4 (i) Lim: X--0 2x-2 +9 (x- 3)2 (ii) Lim 7- 2x – 3

A:

Q: Q7 a) (-) lim x-0 b) (₂) 2 lim 48 3r

A:

Q: Find the limit

A: Given: limx→73xx+2 for evaluating given limit, we put x=7 in given limit

Q: 2. | lim х-5а X — а

A: As the limit expression is defined and not of the indeterminate form thus directly substitute x and…

Q: 2-8x+16) Q5/B: Evaluate lim x-4 \ x2-5x+4

A:

Q: x+5 -lim x-5 r²+25,

A: Given limit, limx→5x+5x2+25

Q: Evaluate the following limits.

A: If any function is continuous within a given interval, then its limit must exist in that interval.…

Q: V x + 9 - 5 lim X--4 x + 4

A: The objective is to evaluate the limit.

Q: (4x-V16x C. lim +3x-5 3x-7* d. lim x0 2x-15*

A: c)…

Q: V5x+4-3 3) lim X-1 x-1

A:

Q: (а) 5x-3 – 4 (i) Lim x-00 2x-2 +9 (х — 3)2 (ii) Lim x-00 x2 7- 2x – 3 2

A:

Q: f-x² + 10x - 25 < g(x) < a² - < 10x + 25 for 4 <x 6, evaluate lim, →5 9(x).

A:

Q: (а) 5x-3 – 4 (i) Lim X00 2x-2 + 9 (х - 3)2 (ii) Lim- X0 x2 7- 2x - 3

A: Here, solving only two subparts of Question number 4 and for the remaining post the question again.…

Q: x2 + 15x + 54 - lim x--6 x² + 36

A:

Q: V2 lim x-2 x- 2

A:

Q: A. lim x? + 3 x -0 B. lim (2x + 5) x -2 C. lim (2x + x2) (2х + x-2

A: Since you have asked a question with multiple parts in a single request, we would be answering only…

Q: (a) lim- エ→4 Vř -16 (b) lim- (1–x)² エー

A:

Q: x² 12x + 27 - lim x → 9 x – 9 -

A: limx→9x2-12x+27x-9

Q: 2x2-ху-у? x²-y² Evaluate lim (х.у) - (1,1) (2) 3. 2

A:

Q: V25+x -5 4-limx-0

A: At first, put x =0 and find the answer, if it results in indeterminate form then use the L'hospitals…

Q: 2 V - 3 lim x – x→0 9 – 5 x 3

A:

Q: 2x?-クyーツ lim メーフ4 x2-メ~12

A:

Q: b) lim x²-25 X-4 X+5

A:

Q: (a) 5x-3 – 4 (i) Lim x-00 2x-2 + 9 (x – 3)2 (ii) Lim x-00 X00 x2 7- 2x – 3 2

A: Since there are multiple questions posted, we will answer the first question posted (Problem 4 (a)).…

Q: answer does not exist, explain why. x - 1- V3x +1 a. lim- х — 5 1- x b. lim (x – 6)²

A:

Q: f(x)= 4x^2 - 14x -8 / x^2 + 4x, if x /= -4 2x-1, if x= -4 Find lim x -&gt; -4 ^ - and  F(-4)

A: The given piecewise function is,