vc(0) = 10V in the following circuit. Determine, (i) The amount of energy stored in the capacitor at t= 0. + VC - 2mF 3 Ohms 4 Ohms 12 Ohms 10
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- Given the circuit below with the switch closed for a long time, then opening at t=0, and with the values R1=193KΩ, R2=186KΩ, R3=107KΩ, calculate the capacitor voltage at t =0.1. Theoretically calculate the voltage across the capacitor in the circuit of Figure 1 when t = 0 s, 5 s, 10 s, 20 s, 30 s, 40 s, and 60 s, assuming that the circuit is under DC conditions when t < 0 s and the switch is opened at t = 0 s. 2. Compare the calculated voltage at t = 20 s with the experimentally measured ∆?.Write a small essay about discharging capacitor then: For the circuit shown, the switch was open for a long time, then it is closed at t=0. Find Vc(t) for t>0. *
- The current (I) flowing in a circuit containing a capacitor that is discharging changes with time (t) according to the equation:I = Io e-t/(CR)A circuit contains a capacitor of 30 x 10-6 F in series with a resistance of 4.7 x 10 5 Ω. If the initial current is 3.5A , calculate the current after 15 s.The circuit shown in the attached image contains a voltage source with emf ε = 2.99 V, a resistor with resistance R = 135 kΩ, and a capacitor with capacitance C = 612 nF. When switch S is set to position a, the three circuit elements are in series. When the switch is in position b, the battery is excluded from the circuit. The switch is initially moved to position a, where it remains for a sufficiently long time that the capacitor is fully charged. The switch is now moved to position b. What is the magnitude of the instantaneous current, in amperes, through the resistor the instant the switch makes contact with terminal b? With time meausred the instant that switch S is closed in position b, calculate the time, in seconds, when the charge on the capacitor is one-half of its maximum value. Calculate the current through the resistor, in amperes, at time t = 155.5 ms after the switch is closed in position b.The switch in the circuit has been in position x for along time. The initial charge on the 60 nF capacitor is zero. At t=0, theswitch moves instantaneously to position y. 1. a) Find vo(t) for t≥0+.2. b) Find v1(t) for t≥0
- The switch in the circuit given below opens at t=0 s after being kept closed for a long enough time. On R=2Ω and Vs =4volts as they are defined as; voltage across the capacitor t=6 second its immediate value (Vc(6)) how many volts?NOTE: Please enter your answer as 2 digits after the comma.In the circuit below, the switch is closed at t=0 s. It is known that the voltage across the capacitor at t=0.2 s is Vc( t = 0.2 ) = 10.31 V. In this case, what will be the voltage Vc( t = 0.1 ) of the capacitor at t=0.1 s? Calculate.No energy is stored in the circuit shown when the input voltagevg jumps instantaneously from 0 to 25 mV 1. Derive the expression for vo(t) for 0≤t≤tsat.2. Find the time tsat when the circuit saturates.
- 2. 7.22 The switch in the circuit has been in the left positionfor a long time. At t=0 it moves to the right position and stays there. 1. a) Write the expression for the capacitor voltage, v(t), for t≥0With X = 5 Ω, initially, the circuit was under a steady state, with switch being in Position 1. It is then switched to Position 2 at t = 0 s. If the current through the inductor is 0.7 A at t = 6 ms, the value of resistor R is __ Ohms.The switch has been in position 1 for a long time. At t = 0, the switch moves instantaneously to position 2. Find the value of R so that 10% of the initial energy stored in the 10mH inductor is dissipated in R in micro-second. Use KCL/KVL and refrain from using formulas.