ver fiat person hmates with a homozygous flat footed person? Allele and Phenotype All Genotype and Phenotype Possibilities Parent Genotypes Punnett Square Answer Letter Phenotype Genotype Phenotype Dad Mom
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- Finish these crosses below:(assume all parents are homozygous for alleles) Cross 1:These are the parents: Sepia Male, Wild Type FemaleWhat are the alleles of the parents? (like Aa and AA / or like XY and XWXW+) Use a Punnett square below to determine the F1 generation phenotypic ratios. What is the phenotypic ratio of the F1? If two F1 individuals mated, what would the F2 phenotypic ratios be?Finish these crosses below:(assume all parents are homozygous for alleles) Cross 3:These are the parents: Wild Type Male; White Eye FemaleWhat are the alleles of the parents? (like Aa and AA / or like XY and XWXW+) Use a Punnett square below to determine the F1 generation phenotypic ratios. What is the phenotypic ratio of the F1? If two F1 individuals mated, what would the F2 phenotypic ratios be?n a container/tub, place 50 pieces ofred paper, 50 pieces of pink paper, and50 pieces of white paper. Let usassume that each color is thephenotypic expression of thegenotypes homozygous dominant AA(red), heterozygous Aa (pink), andhomozygous recessive aa (white).Without looking, randomly pick 20 pieces of paper from your container/tub and assumethat those individuals died upon picking, thus will be removed from your population. a. If you are a picky eater and prefer the white only, what do you think will happen in the genotypic frequency and allelic frequencies of the red, pink and white pieces of papers?
- Please answer all parts of the following question about genes: PLEASE MAKE A PUNNETT SQUARE 1. For the following cross: Aa Bb cc Dd x Aa Bb CC Dd what is the chance of obtaining an individual who: a) shows all dominant traits? b) shows all recessive traits? c) is phenotypically like the second parent? d) is genotypically like the second parent? e) is heterozygous for all alleles? PLEASE MAKE A PUNNETT SQUAREOFFSPRING PHENOTYPE/GENOTYPE DETERMINATIONComplete the following table and list all of the possible offspring phenotypes and genotypes in the space following the table. Use Hitch-hiker’s Thumb and Tongue RollingTable II.PARENTS PHENOTYPE POSSIBLE GENOTYPESYOUMATEShow all possible genotypic here.GametesMATE YouList All Possible Phenotypic Outcomes here:please show genotypic and phenotypic ratio 1.A male French Alpine (WwHH) is crossed with a female French Alpine (wwHh). Where W-White, w-gray, H-Horned, h-Polled. Give the phenotypic and genotypic ratio of their offspring.
- Finish these crosses below:(assume all parents are homozygous for alleles) Cross 1: These are the parents: Sepia Male, Wild Type FemaleWhat are the alleles of the parents? (like Aa and AA / or like XY and XWXW+) Use a Punnett square below to determine the F1 generation phenotypic ratios. What is the phenotypic ratio of the F1? If two F1 individuals mated, what would the F2 phenotypic ratios be? Cross 2: These are the parents: Vestigial Wings, Wild Type Body Male; Wild Type Wings and Ebony Body Female What are the alleles of the parents? (like Aa and AA / or like XY and XWXW+) Use a Punnett square below to determine the F1 generation phenotypic ratios. What is the phenotypic ratio of the F1? If two F1 individuals mated, what would the F2 phenotypic ratios be? Cross 3: These are the parents: Wild Type Male; White Eye Female What are the alleles of the parents? (like Aa and AA / or like XY and XWXW+) Use a Punnett square below to determine the F1 generation phenotypic ratios.…a mother is type a phenotype and two alleles are heterozygous father is blood type O (phenotype) Complete the punnett square to expect genotypes and phenotypes of their offsprings. Mother Father From the punnett square, 4. The probability of offsprings with blood type A is . Answer as a percentage. 5. The probability of offsprings with blood type B is . Answer as a percentage. 6. The probability of offsprings with blood type AB is . Answer as a percentage. 7. The probability of offsprings with blood type O is . Answer as a percentage.Finish these crosses below:(assume all parents are homozygous for alleles) Cross 2:These are the parents: Vestigial Wings, Wild Type Body Male; Wild Type Wings and Ebony Body FemaleWhat are the alleles of the parents? (like Aa and AA / or like XY and XWXW+) Use a Punnett square below to determine the F1 generation phenotypic ratios. What is the phenotypic ratio of the F1? If two F1 individuals mated, what would the F2 phenotypic ratios be?
- Write the number of different kinds of phenotypes,excluding sex, you would see among a large numberof progeny from an F1 mating between individuals ofidentical genotype that are heterozygous for one ortwo genes (that is, Aa or Aa Bb) as indicated. No geneinteractions means that the phenotype determined byone gene is not influenced by the genotype of theother gene.a. One gene; A completely dominant to a.b. One gene; A and a codominant.c. One gene; A incompletely dominant to a.d. Two unlinked genes; no gene interactions; Acompletely dominant to a, and B completelydominant to b.e. Two genes, 10 m.u. apart; no gene interactions; Acompletely dominant to a, and B completely dominant to b.f. Two unlinked genes; no gene interactions; A anda codominant, and B incompletely dominant to b.g. Two genes, 10 m.u. apart; A completely dominantto a, and B completely dominant to b; and withrecessive epistasis between aa and the alleles ofgene B.h. Two unlinked duplicated genes (that is, A and Bperform…Use Punnett Square:The letter that accompanies each trait is representative of the dominant allele. This is the letter you will use when recording the genotypic information for each trait.Read through the descriptions of each trait and determine which phenotype you express. Record your phenotypeNext, determine your genotype. If you express the dominant phenotype, you cannot determine the second allele you carry, so you must list the two possible genotypes. Record this. Question: Widow’s Peak (W): A hairline that forms a downward point in the middle of the forehead is caused by a dominant allele. A smooth hairline is caused by a recessive genotype.Hello Heliodors! (cont.) Trait B Heliodors are either red (R), yellow (Y) or an intermediate phenotype, orange. What is the expected genotypic ratio of the offspring of two orange heliodors? 2 homozygous red: 2 homozygous yellow 1 red: 2 orange: 1 yellow All orange 1 homozygous red: 1 homozygous yellow: 2 heterozygous Answer not given Previous QuestionPreviousNext QuestionNext