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- What is the probability of a parent with O-positive genotype passing O-negative alleles to their offspring 0%, 25%, 50%, 100%? What is the probability of a parent with AB-negative genotype passing B-negative alleles to their offspring 0%, 25%, 50%, 100%? If the frequency of the recessive allele is 0.85, What is 2pq?Below is a table of allele frequencies. Locus 1 Freq(116) = 0.3 Freq(120) = 0.4 Freq(124) = 0.3 Locus 2 Freq(88) = 0.6 Freq(92) = 0.4 Locus 3 Freq(180) = 0.1 Freq(183) = 0.5 Freq(186) = 0.4 You find a sample that has the following genotype: Locus 1: 116/124 Locus 2: 88/92 Locus 3: 186/186 What is the probability of getting a match to this sample by random chance? (Round your answer to 3 significant digits.)
- The human MN blood group is determined by alleles (M and N) for a single gene that code for two specific, codominant markers found on the surface of red blood cells.If two individuals with the MN blood type produce offspring, which phenotypic ratio of offspring would result?1.100% MN2.50% MM: 25% MN: 25% NN3.50% MN: 25% NN: 25% MM4.50% MM: 50% NNMost of the individuals of a certain wildflower population have yellow flowers, although a few are white-flowered. Crosses have demonstrated that allele for yellow flower (Y) is dominant over the allele for white (y). If two white flowered plants are crossed, what fraction of their offspring do you expect to be YELLOW? Show your solution with punnet squareWhich of the following formulas lets you predict the genotypic frequency of the next generation? Select one: A. d = 0.5 lambda / n * sin (theta) B. e = mc2 C. p2 + 2pq + q2 = 1 D. X2 = sum [(o - e)2 / e] E. p + q = 1
- Snuffleups are small, ant-eating mammals that live deep in the jungles of Brazil. They possess a nose that varies between 3 inches long and 19 inches long. The exact length of the nose is determined by quantitative loci. If one crosses a 19-inch nosed snuffleup with one that has a 3-inch nose, one gets F1 offspring with 11-inch noses. When one crosses two F1 individuals, one gets an array of nose lengths from 3 inches to 19 inches long. However, among the F2, 3-inch noses occur only about 1 in 256 offspring and 19-inch noses occur about one in 256 offspring. How many ALLELES are involved in forming this trait?Snuffleups are small, ant-eating mammals that live deep in the jungles of Brazil. They possess a nose that varies between 3 inches long and 19 inches long. The exact length of the nose is determined by quantitative loci. If one crosses a 19-inch nosed snuffleup with one that has a 3-inch nose, one gets F1 offspring with 11-inch noses. When one crosses two F1 individuals, one gets an array of nose lengths from 3 inches to 19 inches long. However, among the F2, 3-inch noses occur only about 1 in 256 offspring and 19-inch noses occur about one in 256 offspring. Two 11-inch nosed F1 individuals are crossed. How often will their progeny have noses 9 inches long? Two 11-inch nosed F1 individuals are crossed. How often will their progeny have noses AT LEAST 15 inches long?based on Harding-Weinberg Equation and the allele frequency table below, what is the frquency of the heteroygous individuals (=genotypes)? show work and expalin rationale sperm p(0.8) q(0.2) egg. P(0.8) p2(0.64) pq(0.16) s. q(0.2). pq(0.16). q2(0.04)
- you observe the following data: 5 white-eyed males, 18 wild-type males, 7 white-eyed females, and 10 wild-type females. What is the white-eyed allele frequency in this generation?Does Hardy-Weinberg equilibrium need to be tested for alleles resulting in only two genotypes?In reference to the following table: F1 ebony flies - 0 F1 non-ebony flies - 560 F1 stubbly flies - 560 F1 non-stubble flies - 0 State whether the allele in the populations giving rise to each phenotype (stubble bristle and ebony bodies) is dominant or recessive.